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hram777 [196]
1 year ago
9

WORD BANK:

Physics
1 answer:
Mkey [24]1 year ago
4 0

Answer:

1. Vector, base

2. Vector, derived

3. Vector, ?

4. Scalar, derived

5. scalar, base

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Which parts of a compound microscope magnify objects?
Yuri [45]
The ocular lens or eyepiece lens
7 0
3 years ago
Read 2 more answers
Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150
alexgriva [62]

Answer:

\phi=4.52 rad

Explanation:

From the question we are told that

Distance b/e antenna's d=9.00m

Frequency of antenna RadiationF_r=120 MHz \approx 120*10^6Hz

Distance from receiver d_r=150m

Intensity of Receiver i= 10

Distance difference of the receiver b/w antenna's (r^2-r^1)=1.8m

Generally the equation for Phase difference \phi is mathematically given by

 \phi=\frac{2\pi}{\frac{c}{f_r}} *(r^2-r^1)

 \phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8

 \phi=\frac{4\pi}{5}  *1.8

<h3>  \phi=4.52 rad</h3>

Therefore phase difference f between the two radio waves produced by this path difference is given as

\phi=4.52 rad

7 0
2 years ago
Find the net charge of a system consisting of 6.25×10^6 electrons and 7.75×10^6 protons. Express your answer using three signifi
jok3333 [9.3K]

Answer:

2.40 x 10⁻¹³ C

Explanation:

n_{e} = number of electrons = 6.25 x 10⁶

q_{e} = charge on electron = - 1.6 x 10⁻¹⁹ C

n_{p} = number of protons = 7.75 x 10⁶

q_{p} = charge on proton =  1.6 x 10⁻¹⁹ C

Net charge is given as

Q = n_{e} q_{e} + n_{p} q_{p}

Q = (- 1.6 x 10⁻¹⁹) (6.25 x 10⁶) + (1.6 x 10⁻¹⁹) (7.75 x 10⁶)

Q = 2.40 x 10⁻¹³ C

6 0
3 years ago
Rita jeptoo of kenya was the first female finisher in the 110th boston marathon. she ran the first 10.0 km in a time of 0.5689 h
stira [4]

Part a

Answer: 17.58 km/h

Average speed=\frac{Total\hspace{1mm}Distance}{Total\hspace{1mm}Time}

Total Distance =10 km

Total time =0.5689 h

\Rightarrow Average speed=\frac{10\hspace{1mm}km}{0.5689\hspace{1mm}h}=17.6 \hspace{1mm}km/h

Part b

Answer: 17.626 km/h

Average speed=\frac{Total\hspace{1mm}Distance}{Total\hspace{1mm}Time}

Total Distance =42.195 km

Total time =2.3939 h

\Rightarrow Average speed=\frac{42.195\hspace{1mm}km}{2.3939\hspace{1mm}h}=17.626\hspace{1mm}km/h

8 0
2 years ago
A 25 kg mass is accelerated by a force at a rate of 5 m/s2. What is the magnitude of the force that accelerates the man?
svlad2 [7]
Force=mass*acceleration
F=ma
F=25*5
F=100 N
8 0
3 years ago
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