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anygoal [31]
3 years ago
14

Which of the following describes metallic character on the periodic table? Question 1 options: A) It increases as you move right

to left within a period and down a group on the periodic table. B) It increases as you move left to right within a period and down a group on the periodic table. C) It increases as you move left to right within a period and up a group on the periodic table. D) It increases as you move right to left within a period and up a group on the periodic table.
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

D

Explanation:

Metallic character decreases as you move across a period in the periodic table from left to right. This occurs as atoms more readily accept electrons to fill a valence shell than lose them to remove the unfilled shell. Metallic character increases as you move down an element group in the periodic table. This is because electrons become easier to lose as the atomic radius increases, where there is less attraction between the nucleus and the valence electrons because of the increased distance between them.

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3 years ago
Fabric A is used to rub a wooden rod. A second piece of Fabric A is used to rub an ebonite rod. It is observed that the wooden r
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6 0
3 years ago
What is the third most common gas found in the air we breathe?
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7 0
3 years ago
Read 2 more answers
If a 12 mg metal ring is heated using 30.0 calories, it’s temperature rises 1.9 degrees Celsius. Calculate the specific heat of
notka56 [123]

Answer:

c = 5505263.16 J/g.°C

Explanation:

Given data:

Mass of ring = 12 mg (12/1000 = 0.012 g)

Calories used = 30.0 cal (30.0 ×4184 = 125520 J)

Temperature increases = 1.9°C

Specific heat of ring = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

125520 J = 0.012 g×c ×1.9°C

125520 J = 0.0228 g.°C ×c

c = 125520 J /  0.0228 g.°C

c = 5505263.16 J/g.°C

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Answer:

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