A wire has a diameter of 2. 0 mm and a length of 32 m and is found to have a resistance of 1. 8 ω having a resistivity of the wire
Resistivity, which is frequently denoted by the letter rho, is mathematically equal to the resistance R of a specimen, such as a wire, multiplied by its cross-sectional area A, and divided by its length l; it is represented by the symbol RA/l. The ohm is the unit of resistance.
A conductor's resistance (R) is inversely proportional to its length (L), with R L. We now know the variables that affect resistivity. Ohm's law and resistors have also been covered in relation to parallel formulae.
The resistance provided by the substance per unit length for unit cross-section is referred to as a conductor's resistivity. Temperature and pressure affect the material's resistivity, which is a property. When compared to the resistivity of insulators, conductors have a low resistivity.
To learn more about resistivity please visit -
brainly.com/question/13612460
#SPJ4
Answer:
533.33 nm
Explanation:
Since dsinθ = mλ for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.
Since the fringes coincide,
m'λ = m"λ'
λ' = m'λ/m"
= 10 × 640 nm/12
= 6400 nm/12
= 533.33 nm
Explanation:
When a truck travels in equal distances in equal intervals of time then we say that the body has got a uniform velocity. In the above example a truck is traveling at 5 miles in all the positions at A, B, and C and all in the intervals of 5 minutes each.
Answer:
55.96kJ
Explanation:
Energy = mass of diethyl ether × enthalpy of vaporization of diethyl ether
Volume (v) = 200mL, density (d) = 0.7138g/mL
Mass = d × v = 0.7138 × 200 = 142.76g
Enthalpy of vaporization of diethyl ether = 29kJ/mol
MW of diethyl ether (C2H5)2O = 74g/mol
Enthalpy in kJ/g = 29kJ/mol ÷ 74g/mol = 0.392kJ/g
Energy = 142.76g × 0.392kJ/g = 55.96kJ
