Ask question

Ask question

All categories

denis-greek [22]

3 years ago

10

Which statement about human behavior would William James support

1 answer:

Grace [21]3 years ago

5 0

If these were the given choices:
Individuals can adapt their behavior to their environment.
Behaviors are learned and reinforced by one's environment.
Personalities are influenced by unconscious conflicts and desires.<span>
Individuals desire personal growth in order to reach their full potential

My answer would be:
INDIVIDUALS CAN ADAPT THEIR BEHAVIOR TO THEIR ENVIRONMENT.

William James had a theory about happiness. He believed that happiness is based on our free will. Being happy is not dependent on our social or biological background, rather it is based on our own decision to achieve happiness in our lives. </span>

You might be interested in

I am a give awayer please like this and say thanks

s344n2d4d5 [400]

Answer:

what.....................

i edited this answer

please mark me as brainlist

4 0

2 years ago

Read 2 more answers

If a sprinter accelerates from rest to 12 m/s north , what is their change in velocity ?

natima [27]

Answer: It would be 12 m/s.

Explanation: It would be this because If you go from rest to sprint it would be 12 m/s. Also, I did this the other day.

5 0

3 years ago

Read 2 more answers

What happens to the volume of a gas when pressure is applied? A. increases B. decreases C. Stays the same D. evaporates

BaLLatris [955]

Answer:

Decreases

Explanation:

8 0

2 years ago

An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

Electric field due to large sheet is given as

$E = \frac{\sigma}{2\epsilon_0}$

$\sigma = 4.00 \times 10^{-12} C/m^2$

now the electric field is given as

$E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}$

$E = 0.225 N/C$

Now acceleration of an electron due to this electric field is given as

$a = \frac{eE}{m}$

$a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}$

$a = 3.97 \times 10^{10}$

Now work done on the electron due to this electric field

$W = F.d$

$d = 0.470 - 0.03$

$d = 0.44 m$

So work done is given as

$W = (ma)(0.44)$

$W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)$

$W = 1.58 \times 10^{-20} J$

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

$W = \frac{1}{2}mv^2 - 0$

$1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2$

$v = 1.86 \times 10^5 m/s$

7 0

2 years ago

A model train traveling at a constant speed around a circular track has a constant velocity

TiliK225 [7]

A model train traveling at a constant speed around a circular track has a constant velocity. FALSE.
Hope this helps you!

3 0

3 years ago