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3 years ago

a man stands on weighing scale in a lift which carries him upwards with acceleration, what happen please tell

Physics

1 answer:

Lapatulllka [165]3 years ago

5 0

He gets heavier due to the upward acceleration of the lift

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Grains of fine california beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide,

kykrilka [37]

The average radius(r) of each grain is r = 50 nanometers = 50*10^-6 meters

Since it is spherical, so

Volume=(4/3)*pi*r^3

V= (4/3)*pi*(50*10^-6)^3

V=5.23599*10^-13 m^3

We are given the Density(ρ) =2600kg/m^3

We know that:

Density(p) = mass(m)/volume(V)

m = ρV

So the mass of a single grain is:

m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg

The surface area of a grain is:

a = 4*pi*r^2

a = 4*pi*(50*10^-6)^2

a = 3.14*10^-8 m^2

Since we know the surface area and mass of a grain, the conversion factor is:

1.361357*10^-9 kg / 3.14*10^-8 m^2

Find the Surface area of the cube:

cube = 6a^2

cube = 6*1.1^2 = 7.26m^2

multiply this by the converions ratio to get:

total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg) / (3.14*10^-8 m^2)

total mass of sand grains = 0.3148 kg = 314.80 g

3 0

3 years ago

a concave mirror of radius of curvature 20cm produces an inverted image three times the size of an object placed on and perpendi

Elis [28]

Answer:

Check attachment for your answer

Good luck

6 0

3 years ago

An astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?

Kamila [148]

Answer:

The answer is

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

$m = \frac{p}{v} \\$

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

$m = \frac{280}{10} = 28 \\$

We have the final answer as

Hope this helps you

3 0

3 years ago

1<br> A truck increases its speed from 15 m/s to 60 m/s in 15 s. Its acceleration is

MAVERICK [17]

Acceleration = (Vf - Vi)/t
Since Vf= 60m/s
Vi= 15m/s
T= 15s
=> a= (60m/s - 15m/s)/15s
= 3
So the acceleration is 3m/s^2

3 0

3 years ago

An 800-g block of ice at 0.00°C is resting in a large bath of water at 0.00°C insulated from the environment. After an entropy c

Allisa [31]

Answer:

Unmeltedd ice = 308.109 g

Explanation:

Gibbs Free energy:

A systems Gibbs Free Energy is defined as the free energy of the product of the absolute temperature and the entropy change less than the enthalpy change.

Therefore, G = ΔH-TΔS

where G is Gibbs Free Energy

ΔH is enthalpy change

T is absolute temperature

ΔS is entropy change

Here since there is a phase change, therefore G will be 0.

∴ΔH = TΔS

Given: Temperature, T = 0°C = 273 K

Entropy change,ΔS = 600 J/K

Latent heat of fusion of water = 333 J/g

∴ΔH = TΔS

∴ΔH = 273 x 600

= 163800 J

So this is the amount of enthalpy that will be used into melting of ice.

∴ΔH = mass of ice melted x latent heat of fusion of water

Mass of ice melted = ΔH / latent heat of fusion of water

= 163800 / 333

= 491.891 g

This is the mass of ice melted.

And initial amount of ice is 800 g

Amount of ice left after melting = Initial amount of ice - amount of ice melted

= 800-491.891

= 308.109 g

Amount of ice remained after melting = 308.109 g

8 0

3 years ago