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Tamiku [17]
3 years ago
14

How can we realize that light travel in straight line ?​

Physics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

It can be seen from the operation of pin-hole camera, formation of shadows and eclipse.

Explanation:

The phenomenon of light traveling in a straight line is known as rectilinear propagation of light.

One this evidence can be seen from the operation of pin-hole camera, which depends on rectilinear propagation of light

Also two natural effects that result from the rectilinear propagation of light are the formation of Shadows and Eclipse.  

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PLEASE HELPPPPPPPP<br> What is the average velocity of a train that goes 86 km in 1.3 hours?
olga_2 [115]
The answer is:

V = d/t d = 86 km t = 1.3 hrs

V = 86 km/ 1.3 hrs

V = 66.15 km/ hrs

I hope this helps!!
5 0
3 years ago
An object floats in a beaker as shown. when it was put into the beaker, it displaced an amount of water into the graduated cylin
Tanzania [10]

Answer:

answer is  C. 10 g

Explanation:

: When an object floats, it displaces an amount of water that has the same mass as itself. Therefore, the mass of the water in the graduated cylinder is equal to the mass of the object. We can see that there are 10 mL of water in the graduated cylinder. We also know that the density of water is 1 g/mL. Since each mL of water has a mass of 1 g, then 10 mL of water has a mass of 10 g. If the mass of the displaced water is 10 g, then the mass of the floating object is also 10 g.

6 0
3 years ago
If my glass is filled with ice and water, will it overflow once the ice has melted?
meriva
No because it will contain the same amount of mass, just in different forms.
7 0
3 years ago
Read 2 more answers
The energy levels of a particular quantum object are -11.7 eV, -4.2 eV, and -3.3 eV. If a collection of these objects is bombard
gogolik [260]

To solve this problem it is necessary to apply an energy balance equation in each of the states to assess what their respective relationship is.

By definition the energy balance is simply given by the change between the two states:

|\Delta E_{ij}| = |E_i-E_j|

Our states are given by

E_1 = -11.7eV

E_2 = -4.2eV

E_3 = -3.3eV

In this way the energy balance for the states would be given by,

|\Delta E_{12}| = |E_1-E_2|\\|\Delta E_{12}| = |-11.7-(-4.2)|\\|\Delta E_{12}| = 7.5eV\\

|\Delta E_{13}| = |E_1-E_3|\\|\Delta E_{13}| = |-11.7-(-3.3)|\\|\Delta E_{13}| = 8.4eV

|\Delta E_{23}| = |E_2-E_3|\\|\Delta E_{23}| = |-4.2-(-3.3)|\\|\Delta E_{23}| = 0.9eV

Therefore the states of energy would be

Lowest : 0.9eV

Middle :7.5eV

Highest: 8.4eV

8 0
3 years ago
Imagine the ball on the left is given a nonzero initial speed in the horizontal direction, while the ball on the right continues
Llana [10]

Let say the height of two balls from the ground is H

now we can use kinematics

s = v_i * t + \frac{1}{2} at^2

now we have

H = \frac{1}{2}gt^2

t = \sqrt{\frac{2H}{g}}

now in the same time ball on the left will cover the horizontal distance between them

v_x = \frac{d}{ t}[/tex[tex]v_x = \frac{3}{\sqrt{\frac{2H}{g}}}

<em>so above is the horizontal speed of the left ball</em>

8 0
3 years ago
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