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2 years ago

How do odd-shaped ceilings, decorative panels, draperies, and glass windows affect echo and noise?

1 answer:

6 0

I think they decrease echo and reduce noise, they do this by either absorbing vibrations or by scattering the sound so that echoes arrive at different times rather than reverberating as a standing wave. An echo is a reflection of a sound that arrives at the listener with a delay after the direct sound. The delay is usually proportional to the distance of the reflecting surface from the source and the listener.

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There is a 120 V circuit in a house that is a dedicated line for the dishwasher, meaning the dishwasher is the only resistor on

Fantom [35]

Answer:

The answer is 6.67 Ohms

Explanation:

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3 years ago

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What would a drummer do to make the sound of a drum give a note of lower pitch?

stiks02 [169]

A drummer would loosen the drum skin in order to make the sound of a drum give a note of lower pitch.
However, I am not entirely sure.

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3 years ago

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In a circus act, a 70 kg clown is shot from a cannon with an initial velocity of 17 m/s at some unknown angle above the horizont

EleoNora [17]

Answer:

$K_{2}=7302.4J$

Explanation:

Given the initial velocity of the clown, his mass and final height we can calculate the final kinetic energy using the <em><u>conservation of total mechanical energy</u></em>

$K_{1}+U_{1}=K_{2}+U_{2}$

$K_{2}=K_{1}+U_{1}-U_{2}$

$K_{2}=\frac{1}{2}mv_{1}^{2}+mgh_{1}-mgh_{2}$

Since $h_{1}=0$

$K_{2}=\frac{1}{2}mv_{1}^{2}-mgh_{2}$

$K_{2}=\frac{1}{2}(70kg)(17m/s)^2-(70kg)(9.8m/s^2)(4.1m)=7302.4J$

$K_{2}=7302.4J$

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3 years ago

What adaptation of a cheetah is shown in the image?

pychu [463]

The adaptation of a cheetah is shown in the image which shows it running is its long and strong legs to run fast which is denoted as option B.

<h3>What is Adaptation?</h3>

These are the physical and behavioral features which ensures that they survive in their changing environment.

Cheetahs are known to have long and strong legs which is the reason why it runs at a very high speed.

Read more about Adaptation here brainly.com/question/29594

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1 year ago

An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first

nordsb [41]

Answer:

a=0.555m/s^2

Explanation:

First we find the distance traveled from the moment the engineer reacts to the car, assuming uniform movement

X=VT

X=(18)(0.45)=8.1m

then we find the distance at which the deceleration begins, which is obtained by subtracting the total distance with the inner result

X=300-8.1=291.9

finally we use the equation for constant acceleration

Vf=0 final speed

Vo=18m/s= initial speed

X=291.9m

(Vf^2-Vo^2)/2X=a

(0-18^2)/(2*291.9)=a

a=0.555m/s^2

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3 years ago

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