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3 years ago

Which of the following statements is not one of Newton's laws of motion?

Physics

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

The answer to your question: d.

Explanation:

a. The rate of change of momentum of an object is equal to the net force applied to the object.

This is the second a law of motion, so this answer is incorrect.

b. In the absence of a net force acting on it, an object moves with constant velocity.

This is the first Newton law of motion, so this option is not correct.

c. For any force, there always is an equal and opposite reaction force.

This is the third law of motion, so this is not the right option.

d. What goes up must come down.

Newton said this sentence, but is not part of the law of motion.

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Could anyone help with number 9?

Alisiya [41]

The answer would be A

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3 years ago

An electron moves with velocity v⃗ =(5.8i−6.7j)×104m/s in a magnetic field B⃗ =(−0.81i+0.60j)T.

Minchanka [31]

Answer:

Fₓ = 0, $F_{y}$ = 0 and $F_{z}$ <em> = - 3.115 10⁻¹⁵ N</em>

Explanation:

The magnetic force given by the expression

F = q v xB

the bold are vectors, the easiest analytical way to determine this force in solving the determinant

$F = q \left[\begin{array}{ccc}i&j&k\\5.8&-6.7&0\\-0.81&0.6&0\end{array}\right] 10^{4}$

F = 1.6 10⁻¹⁵ [ i( 0-0) + j (0-0) + k^( 5.8 0.60 - 0.81 67) ]

F =i^0 + j^0 - k^ 3.115 10⁻¹⁵ N

Fₓ = 0

$F_{y}$ = 0

$F_{z}$ <em> = - 3.115 10⁻¹⁵ N</em>

6 0

3 years ago

1. According to Newton's third law of motion, how are action

san4es73 [151]

Answer:

you couldn't do this on your own or search it up on google

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2 years ago

Two observers are 300 ft apart on opposite sides of a flagpole. The angles of elevation from the observers to the top of the pol

valentina_108 [34]

Answer:

h = 48.077 ft

Explanation:

given,

distance between two observer = 300 ft

angle of elevation to top pole = 16° and 20°

height of the flagpole = ?

now,

Let h be the height of the flagpole

Let x be the distance of the pole

$tan 16^0 = \dfrac{h}{x}$

$x =\dfrac{h}{tan 16^0}$

now,

again applying

$tan 20^0 = \dfrac{h}{300-x}$

$300-x=\dfrac{h}{tan 20^0}$

$300-3.49 h=2.75 h$

$6.24h = 300$

h = 48.077 ft

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3 years ago

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LUCKY_DIMON [66]

Answer:

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Explanation:

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2 years ago