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inessss [21]
3 years ago
8

Which of the answer choices is a true statement? Select all that apply. Metallic elements usually exist as molecules, combining

with atoms of themselves. Metallic elements can exist on their own as individual atoms. Nonmetals usually exist as molecules, combining with atoms of themselves. Nonmetals can exist on their own as individual atoms.
Physics
1 answer:
lianna [129]3 years ago
7 0

Metallic elements can exist on their own as individual atoms.

Nonmetals usually exist as molecules, combining with atoms of themselves.

Nonmetals can exist on their own as individual atoms.

Explanation:

Metallic elements can exist on their own as individual atoms. They have a large radius and are stable enough to freely exist as single atoms. The metallic bonding in them gives them stability.  Example Gold, Silver, Platinum e.t.c

Non-metals are usually found in combined as state as molecules. They are usually joined together by covalent attraction. The bonds are formed with the atoms shares their valence electrons and their octet is completed. For example nitrogen gas, oxygen gas.

Most noble gases are non-metals that exist as individual mono-atomic gases on their own. The gases are stable and have an octet/duet configuration. For example helium gas, neon gas e.t.c

learn more;

Metals and non-metals brainly.com/question/2758034

#learnwithBrainly

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The answer is option B
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aleksklad [387]
(A) We can solve the problem by using Ohm's law, which states:
V=IR
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I is the current through the device
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I= \frac{V}{R}= \frac{220 V}{220 \Omega}=1 A

(B) The resistance of a conductive wire depends on three factors. In fact, it is given by:
R= \rho \frac{L}{A}
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6 0
3 years ago
(a) What is the potential between two points situated 10 cm and 20 cm from a 3.0-μC point charge? (b) To what location should th
julia-pushkina [17]

Answer:

(a) 135 kV

(b) The charge chould be moved to infinity

Explanation:

(a)

The potential at a distance of <em>r</em> from a point charge, <em>Q</em>, is given by

V = -\dfrac{kQ}{r}

where k = 9\times 10^9 \text{ F/m}

Difference in potential between the points is

kQ\left[-\dfrac{1}{0.2\text{ m}} -\left( -\dfrac{1}{0.1\text{ m}}\right)\right] = \dfrac{kQ}{0.2\text{ m}} = \dfrac{9\times10^9\text{ F/m}\times3\times10^{-6}\text{ C}}{0.2\text{ m}}

PD = 135\times 10^3\text{ V} = 135\text{ kV}

(b)

If this potential difference is increased by a factor of 2, then the new pd = 135 kV × 2 = 270 kV. Let the distance of the new location be <em>x</em>.

270\times10^3 = kQ\left[-\dfrac{1}{x}-\left(-\dfrac{1}{0.1\text{ m}}\right)\right]

10 - \dfrac{1}{x} = \dfrac{270000}{9\times10^9\times3\times10^{-6}} = 10

\dfrac{1}{x} = 0

x = \infty

The charge chould be moved to infinity

7 0
3 years ago
A 10.2-kg mass is located at the origin, and a 4.6-kg mass is located at x = 8.1 cm. Assuming g is constant, what is the locatio
goldfiish [28.3K]

Answer:

center of mass of the two masses will lie at x = 2.52 cm

center of gravity of the two masses will lie at x = 2.52 cm

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Explanation:

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here we have

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3 years ago
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Actually what the problem meant about the westward component of the ball’s displacement is the horizontal component of the displacement. To help us better understand the problem, I attached a figure of the situation.

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Therefore the ball has a westward displacement of about 26.77 m

3 0
3 years ago
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