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elena55 [62]
3 years ago
14

4. Are the forces acting on the chandelier unbalanced?​

Physics
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

If it is not an object in motion, all forces are balanced.

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8x = -6. What does x equal?
allsm [11]

Answer:

x= -3/4

Explanation:

4 0
2 years ago
Read 2 more answers
1.The distance moved by objects in a given interval of time can help us to decide which one is faster or slower. Do you agree wi
shutvik [7]

Answer:

The rate of change of distance is defined as speed.

Explanation:

The speed is defined as the rate of change of distance.

Speed = distance/ time

When we know the distance and the time, we get the value of speed. So, e know that who is moving fast or slow.

hen a graph is pltted beteen the distance and time, the slope of the graph gives the value of speed. So, by checking the slopes, hoseslope ismore, the speed is more and thusit is moving faster.

So, i agree with the statement.  

6 0
2 years ago
Which of the following layers in the earth has the highest density?
Ray Of Light [21]
If we are being specific, the inner core has the highest density, but if not then the core in general
5 0
3 years ago
Incident rays parallel to the axis of a concave mirror reflect parallel to the axis.
coldgirl [10]
No they don't.  Incident rays parallel to the axis of a concave mirror
reflect from the mirror's surface and converge at its focal point.
3 0
3 years ago
The density of mobile electrons in copper metal is 8.4 × 1028 m-3. Suppose that i= 4.4 × 1018 electrons/s are drifting through a
neonofarm [45]

Answer: 405.3 minutes

Explanation: In order to explain this problem we have to use the following:

Fisrtly we calculate the volume of the wire, this is given by:

Vwire=π*r^2*L where r and L are the radius and L the length of teh wire, respectively.

Vwire=π*1.25*10^-3*0.26=1.27*10^-6 m^3

then the number of the total electrons in tthe wire volume is given by;

n° electrons in the wire=ρ*Vwire=8.4*10^28*1.27*10^-6 m^3=1.07 *10^23

Finally, considering the current in the wire equal to 4.4*10^18 electrons/s

the time consuming to extract all the electrons from the wire is given by:

t= total electrons in the wire/ current=1.067*10^23/4.4*10^18=24,318 s

equivalent to 405.3 minutes

4 0
2 years ago
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