Answer:
8.56 m/s2
Explanation:
Using law of energy conservation while taking into account of the rotational and translation kinetic energy, when the solid cylinder rolls down the incline we have the potential energy converted to kinetic energy:
where m is the mass, 
is the moments of inertia of the solid cylinder 
is the angular speed of the cylinder
So if you plot a liner chart of h vs 
and get a slope of 6.42 then that means 3/(4g) = 6.42 so 
The gravitational acceleration on this planet is 8.56 m/s2
Answer: The answer position may vary. But the correct answer is D. No; Raul changes more than one variable so the results will be invalid.
Explanation:
Raul's experimental set-up will not produce valid results because he intends to change more than one variable.
One variable that Raul will change is the pot size. According to the description, however, Raul will also change one other variable—the type of flower that is planted. Even though Raul plans on using flowers only, he should use the same type of flower in each pot, not different types.
Valid results are only produced when only one variable is changed at a time.
The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.
<h3>Newton's third law of motion</h3>
Newton's third law of motion states action and reaction are equal and opposite. That is the force applied to an object is equal in magnitude to force experienced by the object but in opposite direction.
From the given question, when the bag exert a certain on the athlete, the athlete also exerts similar force to the bag but in opposite direction.
Thus, the complete sentence is as follows;
The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.
Learn more about Newton's third law of motion here: brainly.com/question/25998091
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Answer:
Explanation:
Discount the time here; it's not important. It doesn't tell you how long it takes the car to stop, it only refers to reaction time, which means nothing in the scheme of things.
The useful info is as follows:
initial velocity = 20 m/s
final velocity = 0 m/s
a = -10 m/s/s
and we are looking for the displacement. Use the following equation:
Δx
where v is the final velocity, v₀ is the initial velocity, a is the deceleration (since it's negative), and Δx is displacement. Filling in:
Δx and
0 = 400 - 20Δx and
-400 = -20Δx so
Δ = 20 meters
