Answer:
when the radius is halved, F becomes 4 times
Explanation:
<u><em>The formula is given by</em></u>
<u><em>When r is halved:</em></u>
=> 
=> 
<u><em>This means when the radius is halved, F becomes 4 times</em></u>
Substance A would have a delta T (change in temp) rise 1/2 the rise in substance B.
Q=mc x delta T
Q= heat energy in Joules
m= mass of substance heated or cooled
c= specific heat
ΔT is change in temp.
Solve for change in temp=. Q/mc
Specific heat and mass are not inversely proportional to heat energy input.
Putting into real world scenario of using water to heat a building.
Specific heat of water is 1.
It takes 1 btu to raise one pound of water 1 degF. at a base of 60 degF
Acetone specific heat is .51
So it takes half the amount of heat input to get a 100 degree ΔT, as compared to water.
No answer is possible until we know the number that belongs after the words "... angular speed of ".
Answer: the ladder
Explanation: since the energized conductor is already in contact with the ladder there by making electric current to flow. The base of the ladder is on the ground there by making the circuit to be complete and causing electrocution.
Answer:
θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²
Explanation:
This is an angular kinematic exercise the equation for the angular position
the particle A
θ = θ₀ + ω₀ t + ½ α t²
They say for the particle B
w₀B = ½ w₀
αB = 2 α
In addition, the particle begins at a time t_1 after particle A, in order to use the same timer, we must subtract this time from the initial
t´ = t - t_1
l
et's write the equation of particle B
θ = θ₀ + w₀B t´ + ½ αB t´2
replace
θ = θ₀ + ½ w₀ (t -t_1) + ½ 2α (t -t_1)²
θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²
