Determine the number of moles NH41+ in 3 moles of (NH4)3PO4.

1 answer:

fomenos2 years ago

3 0

(NH₄)₃PO₄ is a strong electrolyte which fully dissociates into its ions. The balanced equation for the dissociation is
(NH₄)₃PO₄ → 3NH₄⁺ + PO₄³⁻

The stoichiometric ratio between (NH₄)₃PO₄ and NH₄⁺ is 1 : 3

Hence, moles of (NH₄)₃PO₄ / moles of NH₄⁺ = 1 / 3

moles of (NH₄)₃PO₄ = 3 mol

Hence, moles of NH₄⁺ = moles of (NH₄)₃PO₄ x 3
= 3 mol x 3
= 9 mol

Hence, 3 moles of (NH₄)₃PO₄ give 9 moles of NH₄⁺.

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