After 56 days, a 4.0-g sample of phosphorus-32 contains only 0.25 g of isotope. Based on this data,
2 answers:
Answer:
THE HALF LIFE OF PHOSPHORUS-32 ISOTOPE IS 14 DAYS.
Explanation:
Using the Nerst equation of half life;
t1/2 = t * in(2) / in (No/Nt)
where;
t1/2 = half life = the unknown
t = elapsed time = 56 days
No= initial mass of the sample = 4.0 g
Nt = final mass of the sample = 0.25 g
Substituting the values into the equation, we have;
t1/2 = 56 * Ln2 / Ln ( 4/0.25)
t1/2 = 56 * 0.6932 / Ln (16)
t1/2 = 56 * 0.6932 / 2.7726
t1/2 = 38.8192 / 2.7726
t1/2 = 14.001 days.
t1/2 = 14 days.
The half life of the phosphorus- 32 would be 14 days
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Answer : % ionic character is 0.20%
Bonding between the two metals will be purely metallic.
Explanation: For the calculation of % ionic character, we use the formula
where &
are the Pauling's electronegativities.
The table attached has the values of electronegativities, by taking the values of Al and Mn from there,
Putting the values in the electronegativity formula, we get
= 0.20%
Now, there are 3 types of inter atomic bonding
1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms
2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.
3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.
In compound, the % ionic character is minimal that is
0.20% and there are two metal ions present, therefore this compound will have metallic bonding.
