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3 years ago

Can someone help me solve this its a simple series circuit

Physics

1 answer:

daser333 [38]3 years ago

8 0

Answer:

See the explanation below.

Explanation:

Indeed this is a serial circuit, in order to calculate the different questions, we must calculate the current of the circuit. The total resistance of the circuit can be calculated by means of an algebraic summation.

Then using ohm's law,we can calculate the current.

Rt = 2 + 4 + 6 = 12 [ohm]

The current

I = V / Rt

I = 12 / 12

I = 1 [amp]

Therefore the voltage in each resistance will be:

V1 = 2 * 1 = 2 [V]

V2 = 4 * 1 = 4 [V]

V3 = 6 * 1 = 6 [V]

The total voltage will be:

V = V1 + V2 + V3 = 12 [V]

The power can be calculated by multiplying the voltage by the total current.

P = V * I

P = 12 * 1

P = 12 [W]

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How far apart would you have to place the poles of a 1. 5 v battery to achieve the same electric field?

Zarrin [17]

To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m

The potential difference is related to the electric field by:

∆V=Ed

where,

∆V is the potential difference

E is the electric field

d is the distance

what is potential difference?

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

We want to know the distance the detectors have to be placed in order to achieve an electric field of

E=1v/cm=100v/cm

when connected to a battery with potential difference

∆v=1.5v

Solving the equation,we find

$d = \frac{ \:Δv}{e}$

$= \frac{1.5v}{100v/m}$

$= 1.5 \times 10 {}^{ - 2} m$

learn more about potential difference from here: brainly.com/question/28166044

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1 year ago

Drivers should train themselves to scan ahead two seconds looking for ________ hazards and from 10-12 seconds down the road for

xxTIMURxx [149]

Answer:

Immediate, potential

Explanation:

In america there are many safety council .in which drivers are trained. According to american safety council in america the drivers are trained in such a way that they can ahead two seconds so that there will not be any immediate hazards and 10 to 12 seconds down the road for potential hazards

So in the blanks there will be immediate and potential

3 0

3 years ago

Suppose the battery in a clock wears out after moving thousand coulombs of charge through the clock at a rate of 0.5 Ma how long

Ksivusya [100]

Answer:

Hello your question is poorly written below is the complete question

Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?

answer :

a) 231.48 days

b) n = 3.125 * 10^15

Explanation:

Battery moved 10,000 coulombs

current rate = 0.5 mA

<u>A) Determine how long the clock run on the battery. use the relation below</u>

q = i * t ----- ( 1 )

q = charge , i = current , t = time

10000 = 0.5 * 10^-3 * t

hence t = 2 * 10^7 secs

hence the time = 231.48 days