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Lerok [7]
3 years ago
8

What is the acceleration experiance by a car that takes 10s to reach 27m/s from rest

Physics
1 answer:
lina2011 [118]3 years ago
4 0

Magnitude of acceleration = (change in speed) / (time for the change).

Change in speed  =  (27 - 0)  =  27 m/s
Time for the change = 10 s

Magnitude of acceleration =  (27 m/s) / (10 s)  =  2.7 m/s²  .
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A 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new
icang [17]

Answer:

Torque=13798.4 N.m

Explanation:

Given data

Mass of beam m₁=500 kg

Mass of the person m₂=70 kg

length of steel r₁=4.40m

center of gravity of the beam is at r₂=r₁/2 =4.40/2 = 2.20m

To find

Torque

Solution

Torque due to beam own weight

T_{1}=m_{1}gr_{1}\\ T_{1}=500*2.2*9.8\\T_{1}=10780N.m

Torque due to person

T_{2}=m_{2}r_{2}g\\T_{2}=70*(4.40)*(9.8)\\T_{2}=3018.4 N.m

Now for total torque

T_{total}=T_{1}+T_{2}\\T_{total}=10780+3018.4\\T_{total}=13798.4N.m

4 0
3 years ago
Which of the following actions does NO work?
aliya0001 [1]

Answer:

Droping a baseball

Explanation:

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8 0
3 years ago
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julia-pushkina [17]

Answer:

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3 years ago
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-- First, we have to decide how to handle the two resistors.

The effective resistance of resistors in series is the sum
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So in this question, the 4.0 ohms and the 7.5 ohms act like a
single resistor of 11.5 ohms.

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3 0
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Ulleksa [173]
You would use answer 2O g/cm3
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