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Maksim231197 [3]
3 years ago
11

If Goku sprints and tackles a large metal crate doing 18002 J of work over the course of

Physics
1 answer:
Nuetrik [128]3 years ago
3 0
Power is Work/Change in time so it would be 18002/2 which makes power = 9001
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2. A powerful experimental sewing machine is powered by a mass-spring system. This
Alexus [3.1K]

We have that the Number of stitches per sec and he mass of  oscillation motion is mathematically given as

a) Nt=25stitches per sec

b) m=2.033e-5kg

<h3>Number of stitches per sec and he mass of  oscillation motion</h3>

Question Parameters:

This <u>sewing </u>machine is capable of stitching 1,500 stiches in one minute.

If the <em>sewing </em>machine has a spring constant of 0.5 N/m,

Generally the equation for the Number of stitches per sec  is mathematically given as

Nt=N/t

Therefore

Nt=1500/60

Nt=25stitches per sec

b)

Generally the equation for the Time t  is mathematically given as

T=2\pi\sqrt{\frac{m}{k}}

Therefore

0.04=2\pi\sqrt{\frac{m}{0.5}}\\\\m=\frac{0.5*0.04^2}{4\pi^2}

m=2.033e-5kg

For more information on Mass visit

brainly.com/question/15959704

7 0
2 years ago
When multiple forces are at work on an object, the net force is called a ______.
natka813 [3]

When multiple forces are at work on an object, the net force is called a <em>resultant</em>, because it's a sum of vectors, and a sum of vectors is called their resultant.

7 0
3 years ago
An oven mitt is made of a material that is a poor thermal conductor.
ddd [48]

Answer:

D

Explanation:

5 0
3 years ago
Sylvia and Jadon now want to work a problem. Imagine a puck of mass 0.5 kg moving in a circular simulation. Suppose that the ten
leva [86]

Answer:

Tangential speed, v = 2.64 m/s

Explanation:

Given that,

Mass of the puck, m = 0.5 kg

Tension acting in the string, T = 3.5 N

Radius of the circular path, r = 1 m

To find,

The tangential speed of the puck.

Solution,

The centripetal force acting in the string is balanced by the tangential speed of the puck. The expression for the centripetal force is given by :

F=\dfrac{mv^2}{r}

v=\sqrt{\dfrac{Fr}{m}}

v=\sqrt{\dfrac{3.5\ N\times 1\ m}{0.5\ kg}}

v = 2.64 m/s

Therefore, the tangential speed of the puck is 2.64 m/s.

3 0
3 years ago
Physics Homework
katrin2010 [14]

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

4 0
3 years ago
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