Answer:
7.50 m/s^2
Explanation:
The period of a pendulum is given by:
(1)
where
L = 0.600 m is the length of the pendulum
g = ? is the acceleration due to gravity
In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:
And the period is the reciprocal of the frequency:
And by using this into eq.(1), we can find the value of g:
1) 0.0011 rad/s
2) 7667 m/s
Explanation:
1)
The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:
where
is the angular displacement of the object
t is the time elapsed
is the angular velocity
In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is
rad
And the time taken is
Therefore, the angular velocity of the telescope is
2)
For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation
where
v is the linear velocity
is the angular velocity
r is the radius of the circular orbit
In this problem:
is the angular velocity of the Hubble telescope
The telescope is at an altitude of
h = 600 km
over the Earth's surface, which has a radius of
R = 6370 km
So the actual radius of the Hubble's orbit is
Therefore, the linear velocity of the telescope is:
Answer:
a)
b)
Explanation:
From the question we are told that:
Density
Velocity of wind
Dimension of rectangle:50 cm wide and 90 cm
Drag coefficient
a)
Generally the equation for Force is mathematically given by
Therefore Torque
b)
Generally the equation for torque due to weight is mathematically given by
Where
Therefore