Question

What is WgWgW_g, the work done on the block by the force of gravity as the block moves a distance LLL up the incline? Express the work done by gravity in terms of the weight www and any other quantities given in the problem introduction

Answer 1

Answer:

$-mgLsin\theta$

Explanation:

We are given that

Applied force=F

Angle=$\theta$

Distance=L

We have to find the work done by the force  due to gravity.

$g=9.8 m/s^2$

Work done=$mgsin\theta Lcos180^{\circ}+mgcos\theta Lcos90$

$W_g=-mgsin\theta L+mgLcos\theta\times 0$

Where $cos180^{\circ}=-1$

$cos90^{\circ}=0$

$W_g=-mgLsin\theta$

Hence, the work done on the block by the force of gravity as the block moves a distance L up the incline=$-mgLsin\theta$