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Degger [83]
3 years ago
12

A 10000 kg rocket blasts off vertically from the launch pad with a constant upward of 2.25 m/s2 and feels no appreciable air res

istance. When it has reached a height of 525 m, its engine suddenly fails so that only gravity acts on it after that. What is the maximum height that the rocket reaches?
Physics
1 answer:
Sloan [31]3 years ago
4 0

Answer:

The maximum height that the rocket reaches is 645.5 m.

Explanation:

Given that,

Mass = 10000 kg

Acceleration = 2.25 m/s²

Distance = 525 m

We need to calculate the velocity

Using equation of motion

v^2=u^2+2as

Put the value in the equation

v^2=0+2\time2.25\times525

v=\sqrt{2\times2.25\times525}

v=48.60\ m/s

We need to calculate the maximum height with initial velocity

Using equation of motion

v^2=u^2-2gh

h=\dfrac{v^2-u^2}{-2g}

Put the value in the equation

h=\dfrac{0-(48.60)^2}{-2\times9.8}

h=120.50\ m

The total height  reached by the rocket is

h'=s+h

h'=525+120.50

h'=645.5\ m

Hence, The maximum height that the rocket reaches is 645.5 m.

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Svetlanka [38]

The sound intensity level of 100 physics professors talking simultaneously is equal to 72 decibel.

<u>Given the following data:</u>

  • Sound intensity = 52 dB.

<h3>What is sound intensity?</h3>

Sound intensity can be defined as a measure of the power of a sound wave per unit area. Thus, sound intensity is a quantity that can be used to measure the energy of sound and its unit of measurement is Watts per square meter.

<h3>How to calculate the sound intensity level.</h3>

Mathematically, sound intensity level is given by this formula:

\beta = 10 log(\frac{I}{I_{ref}} )

<u>Note:</u> The reference value of sound intensity is equal to 1.0 \times 10^{-12}\;W/m^2

Thus, the sound intensity for one (1) professor is given by:

I_1 = 1.0 \times 10^{-12} \times 10^{5.2}\\\\I_1=1.585 \times 10^{-7}\;W/m^2

For 100 professors, the sound intensity is:

I_{100} = 1.585 \times 10^{-7} \times 100\\\\I_{100}=1.585 \times 10^{-5}\;W/m^2

Substituting the parameters into the formula, we have;

\beta = 10 log(\frac{1.585 \times 10^{-5}}{1.0 \times 10^{-12}})\\\\\beta = 10 log(15.58 \times 10^{6})\\\\\beta = 10 \times 7.2\\\\\beta =72\;dB

Read more on sound intensity here: brainly.com/question/17062836

<u>Complete Question:</u>

One physics professor talking produces a sound intensity level of 52 dB. It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?

7 0
2 years ago
10) The closest star to the earth (other than
Reptile [31]

Answer:

It takes a little, be patient.

8 0
3 years ago
You are moving into an apartment and take the elevator to the 6th floor. Suppose your weight is 790 N and that of your belonging
aliina [53]

Answer:

a) W=26600J

b) W=-12008J

Explanation:

Given the information from the exercise we can calculate the work done by the elevator using the following formula:

W=F*s

a) Considering you and your belongings as a system we know that the elevator is applying a Normal reaction force of:

F=790N+960N=1750N

Since the force applied and the displacement is in the same direction, the work done by the elevator is positive

W=(1750N)(15.2m)=26600J

b) The reaction force applied by the elevator is the same as the weight of the person

F=790N

Since the force applied and the displacement is in opposite direction, the work done by the elevator is negative

W=-(790N)(15.2m)=-12008J

7 0
3 years ago
The result of a wave generator traveling faster than the speed of a wave is:
Vesnalui [34]
The result of a wave generator traveling faster than the speed of a wave is called as a boom. If the wave is a sound wave, it is called a sonic boom. However, if the wave is light, it is called as a luminal boom.  Luminal bloom happens in some industries and is commonly called as the Cherenkov radiation.
4 0
3 years ago
Read 2 more answers
Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What
IgorLugansk [536]

Answer:

Frequency is 213.04\ s^{-1}.

Explanation:

Distance between source 1 from the receiver , S_1 =\sqrt{10^2+22^2}=24.17\ m.

Distance between source 2 from the receiver , S_2=\sqrt{5^2+22^2}=22.56\ m.

Now ,

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We know, for constructive interference path difference should be integral multiple of wavelength .  

Therefore, r=n\times \lambda

It is given that n = 1,

Therefore, \lambda=1.61\ m.

Frequency can be found by , \nu=\dfrac{v}{\lambda}= \dfrac{343}{1.61}=   213.04\ s^{-1} .

Hence, this is the required solution.

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