Answer:
The farther star will appear 4 times fainter than the star that is near to the observer.
Explanation:
Since it is given that the luminosity of the 2 stars is same thus they radiate the same energy per unit time
Consider a spherical wave front of energy 'E' that leaves both the stars (Both radiate 'E' as they have same luminosity)
This Energy is spread over the whole surface area of sphere Thus when the wave front is at a distance 'r' the energy per unit surface area is given by
For the star that is twice away from the earth the distance is '2r' thus we will receive an energy given by
Hence we sense it as 4 times fainter than the nearer star.
A. The bird watcher followed the south trail a distance of five kilometers in 45 minutes.
The momentum of the car is 60,000 kg m/s
The momentum of an object is a vector quantity, whose magnitude is given by
where
m is the mass of the object
v is its velocity
For the car in this problem, we have
m = 2,000 kg
v = 30 m/s
Therefore, the magnitude of its momentum is
Learn more about momentum here:
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One double bond consists 4 electrons, so 2 double bonds means 8 electrons
kinda
can i have brainlyest pls?