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Over [174]
3 years ago
11

What are two ways to change the state of a substance?

Physics
2 answers:
weeeeeb [17]3 years ago
7 0
Solid to liquid
Liquid to solid

By adding or removing heat energy aka thermal energy 
sammy [17]3 years ago
7 0

By adding or removing thermal energy


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Calculate the momentum of a 10kg bowling ball rolling at 2 m/s.
Helen [10]

Answer:

20 kg. m/s

Explanation:

p = mv

m = 10 kg

v = 2 m/s

p = 10 × 2

p = 20 kg m/s

5 0
3 years ago
A 100-W lightbulb is placed in a cylinder equipped with a moveable piston. The lightbulb is turned on for 0.010 hour, and the as
Taya2010 [7]

Answer:

w =  - 508.53 joules

q = - 3091.47 joules

Explanation:

Let us convert the time in hours into seconds

0.010* 3600\\= 36

Change in internal energy

\delta E = p * \delta t

where E is the internal energy in Joules

p is the power in watts

and t is the time in seconds

\delta E = - 100 * 36\\

\delta E = - 3600 Joules

Amount of work done by the system

w = - P * \delta V

where P is the pressure and V is the volume

Substituting the given values in above equation, we get -

w = - 1 * ( 5.92 -0.90)\\

w = -5.02 liter-atmospheres

Work done in Joules

- 5.02 * 101.3\\= 508.53Joules

q = \delta E - w\\

Substituting the given values we get -

q = - 3600 - (-508.53)\\q = - 3091.47

Thus

w =  - 508.53 joules

q = - 3091.47 joules

7 0
3 years ago
Anyone know the answer ?
dlinn [17]
Momentum = mass x velocity, so 500kg x 2m/s = 1000 kg m/s
5 0
3 years ago
Read 2 more answers
Which sequence shows electromagnetic waves arranged in a decreasing order of their wavelengths?
Hunter-Best [27]

Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.

8 0
3 years ago
A Meteorite Strikes On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, leaving a dent 22 cm deep in the tru
vagabundo [1.1K]

Answer:

Acceleration of the meteorite, a=-38409.09\ m/s^2

Explanation:

It is given that,

A Meteorite after striking struck a car, v = 0

Initial speed of the Meteorite, u = 130 m/s

Distance covered by Meteorite, s = 22 cm = 0.22 m

We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{-(130)^2}{2\times 0.22}

a=-38409.09\ m/s^2

So, the deceleration of the Meteorite is -38409.09\ m/s^2. Hence, this is the required solution.

7 0
3 years ago
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