The electric output of the plant is 48.19 MW
First we need to calculate the water power, it is given by the formula
WP=ρQgh
Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head
Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW
Now the overall efficiency of the hydroelectric power plant is given as
η=
Plugging the values in the above equation
0.84=EP/57.38
EP=48.19 MW
Therefore, the electric output of the plant is 48.19 MW.
#2
As it is given here
initial speed is
After 4 seconds the final speed is
so here we can use the formula of acceleration using kinematics
so here it will accelerate at 2 m/s^2 rate.
#3
As it is given here
initial it starts from rest
After 2.5 seconds the final speed is
so here we can use the formula of acceleration using kinematics
so here it will accelerate at 6 m/s^2 rate.
#4
i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.
Answer:
74.4 kilowatts or 99.8 horsepower
Explanation:
The explanation is in the attachment.
