Answer:
![u_K=0.862](https://tex.z-dn.net/?f=u_K%3D0.862)
Explanation:
The force of friction between the quails feet and the ground is:
![F=m*a](https://tex.z-dn.net/?f=F%3Dm%2Aa)
![F_K=m*a](https://tex.z-dn.net/?f=F_K%3Dm%2Aa)
![F_K=u_k*m*g](https://tex.z-dn.net/?f=F_K%3Du_k%2Am%2Ag)
![u_K*m*g=m*a_c](https://tex.z-dn.net/?f=u_K%2Am%2Ag%3Dm%2Aa_c)
![u_K*g=a](https://tex.z-dn.net/?f=u_K%2Ag%3Da)
![u_K=\frac{a_c}{g}](https://tex.z-dn.net/?f=u_K%3D%5Cfrac%7Ba_c%7D%7Bg%7D)
![a_c=\frac{v^2}{r}](https://tex.z-dn.net/?f=a_c%3D%5Cfrac%7Bv%5E2%7D%7Br%7D)
So the coefficient of static is solve
![u_K=\frac{\frac{v^2}{r}}{g}](https://tex.z-dn.net/?f=u_K%3D%5Cfrac%7B%5Cfrac%7Bv%5E2%7D%7Br%7D%7D%7Bg%7D)
![u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}](https://tex.z-dn.net/?f=u_K%3D%5Cfrac%7Bv%5E2%7D%7Br%2Ag%7D%3D%5Cfrac%7B%282.6m%2Fs%29%5E2%7D%7B0.80m%2A9.8m%2Fs%5E2%7D)
![u_K=0.862](https://tex.z-dn.net/?f=u_K%3D0.862)
Answer:
![E = 9.66\times 10^{-6} N/C](https://tex.z-dn.net/?f=E%20%3D%209.66%5Ctimes%2010%5E%7B-6%7D%20N%2FC)
direction is Horizontal
Explanation:
As we know that the string is horizontal here
so the tension force in the string is due to electrostatic force on it
now we will have
![F = qE](https://tex.z-dn.net/?f=F%20%3D%20qE)
so here the force is tension force on it
![F = 6.57 \times 10^{-2} N](https://tex.z-dn.net/?f=F%20%3D%206.57%20%5Ctimes%2010%5E%7B-2%7D%20N)
![Q = 6.80 \times 10^3 C](https://tex.z-dn.net/?f=%20Q%20%3D%206.80%20%5Ctimes%2010%5E3%20C)
now we have
![6.57 \times 10^{-2} = (6.80 \times 10^3)E](https://tex.z-dn.net/?f=6.57%20%5Ctimes%2010%5E%7B-2%7D%20%3D%20%286.80%20%5Ctimes%2010%5E3%29E)
![E = 9.66\times 10^{-6} N/C](https://tex.z-dn.net/?f=E%20%3D%209.66%5Ctimes%2010%5E%7B-6%7D%20N%2FC)
direction is Horizontal
Take for example driving by with a cake in your hand, then dropping it while going 30 mph. It will not drop directly down, it will gradually go in the direction you were driving while falling.
This is true I believe, if I'm interpreting correctly.
Answer:
103.1 V
Explanation:
We are given that
Initial circumference=C=168 cm
![\frac{dC}{dt}=-15cm/s](https://tex.z-dn.net/?f=%5Cfrac%7BdC%7D%7Bdt%7D%3D-15cm%2Fs)
Magnetic field,B=0.9 T
We have to find the magnitude of the emf induced in the loop after exactly time 8 s has passed since the circumference of the loop started to decrease.
Magnetic flux=![\phi=BA=B(\pi r^2)](https://tex.z-dn.net/?f=%5Cphi%3DBA%3DB%28%5Cpi%20r%5E2%29)
Circumference,C=![2\pi r](https://tex.z-dn.net/?f=2%5Cpi%20r)
![r=\frac{C}{2\pi}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7BC%7D%7B2%5Cpi%7D)
cm
![\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}(-15)=-\frac{15}{2\pi} cm/s](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%5Cpi%7D%5Cfrac%7BdC%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B2%5Cpi%7D%28-15%29%3D-%5Cfrac%7B15%7D%7B2%5Cpi%7D%20cm%2Fs)
![\int dr=-\int \frac{15}{2\pi}dt](https://tex.z-dn.net/?f=%5Cint%20dr%3D-%5Cint%20%5Cfrac%7B15%7D%7B2%5Cpi%7Ddt)
![r=-\frac{15}{2\pi}t+C](https://tex.z-dn.net/?f=r%3D-%5Cfrac%7B15%7D%7B2%5Cpi%7Dt%2BC)
When t=0
![r=\frac{168}{2\pi}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B168%7D%7B2%5Cpi%7D)
![\frac{168}{2\pi}=C](https://tex.z-dn.net/?f=%5Cfrac%7B168%7D%7B2%5Cpi%7D%3DC)
![r=-\frac{15}{2\pi}t+\frac{168}{2\pi}](https://tex.z-dn.net/?f=r%3D-%5Cfrac%7B15%7D%7B2%5Cpi%7Dt%2B%5Cfrac%7B168%7D%7B2%5Cpi%7D)
E=![-\frac{d\phi}{dt}=-\frac{d(B\pi r^2)}{dt}=-2\pi rB\frac{dr}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5Cphi%7D%7Bdt%7D%3D-%5Cfrac%7Bd%28B%5Cpi%20r%5E2%29%7D%7Bdt%7D%3D-2%5Cpi%20rB%5Cfrac%7Bdr%7D%7Bdt%7D)
![E=-2\pi(-\frac{5}{2\pi}t+\frac{168}{2\pi})B\times -\frac{15}{2\pi}](https://tex.z-dn.net/?f=E%3D-2%5Cpi%28-%5Cfrac%7B5%7D%7B2%5Cpi%7Dt%2B%5Cfrac%7B168%7D%7B2%5Cpi%7D%29B%5Ctimes%20-%5Cfrac%7B15%7D%7B2%5Cpi%7D)
t=8 s
B=0.9
![E=2\pi\times \frac{15}{2\pi}\times 0.9(-\frac{15}{2\pi}(8)+\frac{168}{2\pi})](https://tex.z-dn.net/?f=E%3D2%5Cpi%5Ctimes%20%5Cfrac%7B15%7D%7B2%5Cpi%7D%5Ctimes%200.9%28-%5Cfrac%7B15%7D%7B2%5Cpi%7D%288%29%2B%5Cfrac%7B168%7D%7B2%5Cpi%7D%29)
![E=103.1 V](https://tex.z-dn.net/?f=E%3D103.1%20V)
Answer: because increasing biodiversity can influence ecosystem functions such as productivity and variety and even the likelihood that a particular species is discovered by a comminity
Explanation: