Distance=speed times time
speed=5mph=5
time=30mins=30/60hr=1/2hr
so
distance=speed times time
he will run 2.5 miles in 30 mins at the speed of 5mph
Answer: Ф = 17.2657 ≈ 17°
Explanation:
we simply apply ET =0 about the ending of the rod
so In.g.L/2sinФ - In.a.L/2cosФ = 0
g.sinФ - a.cosФ = 0
g.sinФ = a.cosФ
∴ tanФ = a/g
Ф = tan⁻¹ a / g
Ф = tan⁻¹ ( 10 / 32.17405)
Ф = tan⁻¹ 0.31080948777
Ф = 17.2657 ≈ 17°
Therefore the angle of rotation of the rod during this acceleration is 17.2657 ≈ 17°
Answer:
Exercise helps people lose weight and lower the risk of some diseases. Exercising regularly lowers a person's risk of developing some diseases, including obesity, type 2 diabetes, and high blood pressure. Exercise also can help keep your body at a healthy weight. Exercise can help a person age well.
Answer:
0.71ohms
Explanation:
AC and CB are in series hence the total resistance is 3+2=5ohms
AD and DB are in series hence the total resistance is 3+2=5ohms
These resistances are parallel to resistance AB
Let the equivalent resistance be R.
For resistances in parallel
Hence the total resistances are:
5//1//5
1/R =1/5 + 1/1 +1/5 = 1+5+1 /5 = 7/5
Hence the total resistance is R= 1/ 7/5 = 1×5/7= 5/7=0.71ohms
Answer:
v = 31.84 cm/s or 0.318 m/s
the speed of the water leaving the end of the hose is 31.84 cm/s or 0.318 m/s
Explanation:
Given;
Diameter of hose d = 2.76 cm
Volume filled V = 20.0 L = 20,000 cm^3
Time t = 1.45 min = 105 seconds
The volumetric flow rate of water is;
F = V/t = 20,000cm^3 ÷ 105 seconds
F = 190.48 cm^3/s
The volumetric flow rate is equal the cross sectional area of pipe multiply by the speed of flow.
F = Av
v = F/A
Area A = πd^2/4
Speed v = F/(πd^2/4)
v = 4F/πd^2 ......1
Substituting the given values;
v = (4×190.48)/(π×2.76^2)
v = 31.83767439628 cm/s
v = 31.84 cm/s or 0.318 m/s
the speed of the water leaving the end of the hose is 31.84 cm/s or 0.318 m/s
