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deff fn [24]
3 years ago
6

Water from a lake changes to a gas state in the process of what?

Chemistry
2 answers:
boyakko [2]3 years ago
7 0
Of heating. Or when the lake is exposed to boil because of the temperature.
Thepotemich [5.8K]3 years ago
6 0
The scientific term is evapouration but heating works too
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Hydrogen fuel cells are a promising alternative to gasoline engines in part because they release water instead of carbon dioxide
enot [183]

Answer:

The correct answer is option (B) Two molecules of H2 and a molecule of O2 must collide at one time

Explanation:

2H2(g) + O2(g) → 2 H2O(g)

   2             1            2

Considering the given reaction, for water molecule to be form, two molecules of hydrogen and one molecule of oxygen must collide at the same time. The product obtained from the collision is two molecules of water as steam. 2 H2O(g)

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3 years ago
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Which is correct if 15,390,000 is rounded to two significant figures?
BARSIC [14]

Answer:

Explanation:

Remark

This is one of those questions that you need the choices. You can't tell what you should enter. For example, in scientific notation, you would get 1.5*10^7.

Or you could keep it as an integer and round to two places 150,000,000,

I would pick scientific notation if you know how to use it. Otherwise use the interger format.

7 0
2 years ago
50 Points for whoever does it and shows their work. Maya has four glasses of milk. The temperature and the amount of milk in eac
galina1969 [7]

Answer:

A. 20 grams of milk at 10°C

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Since we refrigerate milk, it would be cooler than the room temperature, which standard norm is 25°C. So the milk has to be colder than the room temperature. Therefore, our answer is A.

3 0
3 years ago
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1 pentagram equals how many grams
Fofino [41]

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5 grams.

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7 0
3 years ago
What is the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol)?
NemiM [27]

the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g

The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn

3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2

the formula is n= mass/M so, now substituting values

m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3

so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g

so mass of aluminum oxide obtained = 1.36g

To learn more about Mass:

brainly.com/question/19694949

#SPJ4

3 0
2 years ago
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