Answer: a. 198.6J b. - 198.6J
Explanation: Parameters given:
m = 15kg
g = 9.8m/s²
∅ = 12°
a. Work done by the force Fp on the cart if the ramp is 6.5m long.
Given the formula, Fp = Mgsin∅ = 15 x 9.8 x sin12° = 30.56N
Therefore Work done (Wp) = Fp x Ramp Length = 30.56 x 6.5 = 198.64Nm or 198.6J
b. The work done by the force mg on the cart.
Since the cart is being pushed upwards, it acts against gravity with its direction of motion. Taking into account the formula from the previous answer for Work Done (Wg) = Fmg x distance
= 15kg x -9.8m/s² x Sin12° x 6.5m
= - 198.6J
Answer:
35.2 ps
Explanation:
Hello!
A US short ton is equal to 2 000 pounds, therefore:
2.25 tons = 4500 pounds
Now lets convert the area of each tire footprint:
1 cm = 0.393701 in
12.5 cm = 4.92126 in
16.5 cm = 6.49607 in
Therefore, the area of the footprint is: 31.9688 in^2
Then, the pressure exerted by the car is given by the weigth devided by the total area, that is 4 times the area of the footprint :
4500 /(4 * 31.9688) psi = 35.1906 psi
Rounding to the first tenth
35.2 psi
Answer:
The answer is positively B.
There are so many base pairs that there are individual differences.
Confirmed by my Forensics test today.
Explanation:
What exactly has to be in the presentation ???
Answer:
the capacitive reactance is reduced by a factor 2
Explanation:
The capacitive reactance is given by:
where
f is the frequency of the source
C is the capacitance
In this case, the frequency of the source is doubled:
f' = 2f
while the capacitance does not change. So the new capacitive reactance will be
so the capacitive reactance is reduced by a factor 2.
