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andre [41]
3 years ago
14

Which of the following statements correctly describes the models put forth by Ptolemy and Copernicus to explain the universe? A.

Through observations, both astronomers presented models where the earth remained stationary. B. Both of the models were easy to understand and thus were well received by the public almost instantly. C. The sun was in the center of Ptolemy's model, but the Earth was in the center of Copernicus' model. D. The model developed by Copernicus was simpler and had less inconsistencies than Ptolemy’s model.
Physics
2 answers:
FrozenT [24]3 years ago
8 0
The correct option is D. 
The model developed by Ptolemy has a lot of inconsistency and during the middle age additional explanation was offered for the claims made by the model. The model was very complicated because it was based on erroneous assumptions.
Copernicus model was simpler and some of his claims were correct.<span />
Nimfa-mama [501]3 years ago
8 0

Answer:

the answer is D

Explanation:

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Answer:

global winds A

Explanation:

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If the window is 11 m above the ground, find the time the stone is in flight.
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d=vi*t+(1/2)gt²

d=11 m
g=9.8 m/s²
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11 m=0 m/s*t+(1/2)9.8 m/s²t²
11 m=4.9 m/s²t²
t²=11 m / 4.9 m/s²
t=√(11 m / 4.9 m/s²)=1.489... s≈1.5 s

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A 0.90-kg falcon is diving at 28.0 m/s at a downward angle of 35° . It catches a 0.325-kg pigeon from behind in midair. What is
pashok25 [27]

Answer:

22.11 m / s

Explanation:

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initial velocity of falcon = 28 cos 35 i - 28 sin 35 j  

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momentum = .9 ( 28 cos 35 i - 28 sin 35 j  )

= 20.64 i - 14.45 j

initial velocity of pigeon

= 7 i

initial momentum = .325 x 7i

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If final velocity of composite mass of falcon and pigeon be V

Applying law of conservation of momentum

( .9 + .325) V = 20.64 i - 14.45 j +2.275 i

V = ( 22.915 i - 14.45 j ) / 1.225

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= √ [  (18.7 )² + ( 11.8 )²]

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An astronaut has a mass of 75 kg and is floating in space 500 m from his 125,000 kg spacecraft. What will be the force of gravit
nikdorinn [45]

Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

1. Determination of the force of attraction.

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Mass of spacecraft (M₂) = 125000 Kg

Distance apart (r) = 500 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

F = 2.5×10¯⁹ N

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2. Determination of the acceleration of the astronaut.

Mass of astronaut (m) = 75 Kg

Force (F) = 2.5×10¯⁹ N

Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

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Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

5 0
3 years ago
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