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Contact [7]
4 years ago
15

How could you increase the number of snowmen destroyed by the sled sliding down the hill? SledAQ1 A. Increase the starting heigh

t of the sled. B. Increase the mass of the sled. C. Increase the starting kinetic energy of the sled. D. All of the above.
Physics
2 answers:
Dima020 [189]4 years ago
8 0
To increase the number of snowmen destroyed, you would want more energy and all of the above would increase the energy of the system so D.
Afina-wow [57]4 years ago
8 0

All of above is answer

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A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
Margaret [11]

Hi there!

\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

Recall the equation for angular momentum:

L = I\omega

We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

I_m = moment of inertia of the merry-go-round (kgm²)

\omega_m = angular velocity of merry go round (rad/sec)

\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\omega = \frac{v}{r}

L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

Now, we must solve for the boy's moment of inertia:

I = MR^2\\I = 20(3^2) = 180 kgm^2

Use the above equation for conservation of momentum:

600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

8 0
3 years ago
The car has a constant deceleration of 4.20 m/s^2. If its initial velocity was 24.0 m/s, how long does it take to come to a stop
nalin [4]

Answer:

The time is 5.71 sec.

Explanation:

Given that,

Acceleration a= -4.20 m/s^2

Initial velocity = 24.0 m/s

We need to calculate the time

Using equation of motion

v = u+at[/tex]

Where, v = final velocity

u = inital velocity

t = time

a = acceleration

Put the value into the formula

0 =24.0 +(-4.20)\times t

t = \dfrac{-24.0}{-4.20}

t=5.71\ sec

Hence, The time is 5.71 sec.

5 0
4 years ago
A ball traveling with an initial momentum of 4.5 kgm/s bounces off a wall and comes back in the opposite direction with a moment
irinina [24]

Answer:

-7.5 kg m/s

Explanation:

Initial momentum (p1) = 4.5 kg m/s

final momentum (p2) = -3.5 kg m/s

We have to find out the change in momentum , As linear momentum is a vector quantity. So, we have to use the vector form to solve the momentum change . Means we have to take the sign of momentum also.

Change in momentum = Final momentum - initial momentum

So,

Change in momentum = p2 - p1

Insert values from question,

Change in momentum = -3.5 kg m/s - 4 kg m/s

So, change in momentum = -7.5 kg m/s

3 0
3 years ago
What is measurement ?​
bazaltina [42]

Answer:

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events

7 0
3 years ago
Read 2 more answers
When sound waves strike the eardrum, this membrane vibrates with the same frequency as the sound. The highest pitch that typical
kherson [118]

Answer:

Explanation:

Time period, T = 50 μs = 50 x 10^-6 s

Frequency is defined as the number of oscillations or vibrations completed in one second.

The reciprocal of time period is called frequency.

f = 1 / T

f = 1 / (50 x 10^-6)

f = 20,000 Hz

Angular frequency, ω = 2 x π x f

ω = 2 x 3.14 x 20,000

ω = 125600 rad/s

7 0
3 years ago
Read 2 more answers
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