The correct unabbreviated electron configuration is as below
Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2
Strontium - 1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2
Carbon =1S2 2S2 2P2
<u><em> Explanation</em></u>
vanadium is in atomic number 23 in the periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2
Strontium is in atomic number 38 in periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4s2
Carbon is in atomic number 6 in periodic table therefore its electron configuration is 1s2 2s2 2p2
Answer:
<em>At equilibrium, the rate of the forward, and the reverse reactions are equal.</em>
Explanation:
In an equilibrium chemical reaction, the rate of forward reaction, is equal to the rate of reverse reaction. Note that the reactions does not cease at equilibrium, but rather, the reactants are converted to product, at the same rate at which the product is also being converted into the reactants in the reaction. When chemical equilibrium is reached, a careful calculation of the value of equilibrium constant is approximately equal to 1.
NB: If the value of equilibrium constant is far far greater than 1, then the reaction will favors more of the forward reaction, and if far far less than 1, the reaction will favor more of the reverse reaction.
Answer:
M = 1.18 mol/L
Explanation:
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = moles ,
w = given mass ,
m = molecular mass .
From the information of the question ,
w = 78.3 g
As we known ,
molecular mass of 
is 189.36 g/mol
m = 189.36 g/mol
moles can be calculated as -
n = 0.413 mol
MOLARITY -
Molarity of a substance , is the number of moles present in a liter of solution .
M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
From the question ,.
V = 350 mL
Since , 1 mL = 10⁻³ L
V = 0.350 L
n = 0.413 mol
Molarity can be calculated as -
M = 1.18 mol/L
Answer is: 5,9.
Effusion is leakage of gas
through a small hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
</span>M(O₂) = 32g/mol.
M(CO₂) = 44g/mol.
t₁ = 5s.
t₂ = ?
t₂/t₁ = √(M(CO₂)/M(O₂)).
t₂ = 1,17·5s = 5,9s.
Answer:
Explanation:
16. 12
17. 8
18. 9
19. 10
20. 5
21. 15
22.8
23. 24
24. 12
25. 3 i guess( some one comment for 25th pls)
26. 2
