Describe the term molarity as it relates to an acid or base.

2 answers:

6 0

Molarity, also known as concentration in amount of matter, is the ratio between the amount of solute matter, measured in mol (n1), and the volume of solution in liters (V). This concentration is measured in mol per liter (mol / L). It is often called by some authors molar concentration, but the correct terms are "concentration in mol / L" or "concentration in amount of matter".

Consider the gastric juice that our stomach produces for the purpose of performing the digestion process. In fact, it is a hydrochloric acid (HCl) solution at a concentration of 0.01 mol / L. This means that for every liter of gastric juice there is 0.01 mol HCl. The same goes for basic concentration solutions. Consider a NaOH solution at a concentration of 0.02 mol NaOh. This means that if each NaOh litter is present, there is 0.02 mol of NaOh.

Sidana [21]3 years ago

4 0

Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. Acids and bases can be measured through the concentrations of H+ and OH- ions in units of molarity. Hope this helps.

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Determine total H for bonds broken and formed, the overall change in H, and the final answer with units. Is it ENDOthermic or EX

Mrac [35]

E(Bonds broken) = 1371 kJ/mol reaction
E(Bonds formed) = 1852 kJ/mol reaction

ΔH = -481 kJ/mol.
The reaction is exothermic.

<h3>Explanation</h3>

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
ΔH(Breaking bonds) = +1371 kJ/mol

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.
ΔH(Forming bonds) = - 1852 kJ/mol

Heat of the reaction:

$\Delta H_{\text{rxn}} = \Delta H(\text{Breaking bonds}) + \Delta H(\text{Forming bonds})\\\phantom{ \Delta H_{\text{rxn}}} = +1371 + (-1852) \\\phantom{ \Delta H_{\text{rxn}}} = -481 \; \text{kJ} / \text{mol}$

$\Delta H_{\text{rxn}}$ is negative. As a result, the reaction is exothermic.

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