All categories

3 years ago

Describe the term molarity as it relates to an acid or base.

2 answers:

6 0

Molarity, also known as concentration in amount of matter, is the ratio between the amount of solute matter, measured in mol (n1), and the volume of solution in liters (V). This concentration is measured in mol per liter (mol / L). It is often called by some authors molar concentration, but the correct terms are "concentration in mol / L" or "concentration in amount of matter".

Consider the gastric juice that our stomach produces for the purpose of performing the digestion process. In fact, it is a hydrochloric acid (HCl) solution at a concentration of 0.01 mol / L. This means that for every liter of gastric juice there is 0.01 mol HCl. The same goes for basic concentration solutions. Consider a NaOH solution at a concentration of 0.02 mol NaOh. This means that if each NaOh litter is present, there is 0.02 mol of NaOh.

Sidana [21]3 years ago

4 0

Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. Acids and bases can be measured through the concentrations of H+ and OH- ions in units of molarity. Hope this helps.

You might be interested in

Help me ples HELP HELP HELP HELP HELP

Darya [45]

Answer:

Explanation:autotroph and photosynthesis

sorry if I am wrong I am dumb. :( :(

I found it on google.

God bless, stay safe, and good luck! :) :)

3 0

3 years ago

What mass (in grams) of Mg(NO3)2 is present in 151 mL of a 0.350 M solution of Mg(NO3)2?

Mademuasel [1]

Answer is: A) 7.84 g.

V(Mg(NO₃)₂) = 151 mL ÷ 1000 mL/L.

V(Mg(NO₃)₂) = 0.151 L; volume of the magnesium nitrate.

c(Mg(NO₃)₂) = 0.352 M; molarity of the solution.

n(Mg(NO₃)₂) = V(Mg(NO₃)₂) · c(Mg(NO₃)₂).

n(Mg(NO₃)₂) ) = 0.151 L · 0.352 mol/L.

n(Mg(NO₃)₂) = 0.0531 mol; amount of the substance.

M(Mg(NO₃)₂) = Ar(Mg) + 2Ar(N) + 6Ar(O) · g/mol.

M(Mg(NO₃)₂) = 24.3 + 2·14 + 6·16 · g/mol.

M(Mg(NO₃)₂) = 148.3 g/mol; molar mass.

m(Mg(NO₃)₂) = n(Mg(NO₃)₂) · M(Mg(NO₃)₂).

m(Mg(NO₃)₂) = 0.0531 mol · 148.3 g/mol.

m(Mg(NO₃)₂) = 7.84; mass of magnesium nitrate.

6 0

3 years ago

Read 2 more answers

Consider the following system at equilibrium where \Delta H° = 18.8 kJ, and Kc = 9.52×10-2, at 350 K.

slega [8]

Answer:

1. C. remains the same. 2. C. is less than Kc. 3. B. run in the reverse direction to reestablish equilibrium. 4. A. increase.

Explanation:

At constant temperature, the equilibrium concentration has not effect on the equilibrium constant because the rate constants do not change with change in the concentrations or amounts of the reactants or products. Change in the concentration of one reactant or product causes the concentration of the others to change so as to maintain a constant value for the equilibrium constant. On the other hand, the reaction quotient is used to measure the relative amounts of reactants and products during a chemical reaction at any point in time. The value of the reaction quotient shows the direction of the chemical reaction.

Therefore, when 0.31 moles of CCl4(g) are removed from the equilibrium system at constant temperature:

1. the value of Kc remains the same

2. the value of Qc is less than Kc

3. the reaction must run in the reverse direction to reestablish equilibrium

4. the concentration of $CH_{4}$ will increase because product will be converted to reactants to reestablish equilibrium.

7 0

3 years ago

To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate i

enyata [817]

Answer: There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$ .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

$0.0880M=\frac{\text{Moles of acetic acid}\times 1000}{30.6ml}\\\\\text{Moles of acetic acid}=\frac{0.0880\times 30.6}{1000}=0.00269mol$

Thus there are 0.00269 moles of acetic acid in buffer.

8 0

2 years ago

I WILL GIVE BRAINLIEST ANSWER IN 5 MINS

snow_lady [41]

Physical Properties: Sodium bicarbonate is an odorless, white crystalline solid or fine powder. It has a slightly alkaline taste. Its density is 2.20 g mL-1 and it decomposes in temperatures above 50 ºC. The decomposition yields to sodium carbonate. It is highly soluble in water and poorly soluble in acetone and methanol. It is insoluble in ethanol.

Chemical Properties: Sodium bicarbonate is an amphoteric compounds, it means the compound has a character acids an basic at the same time. It is highly soluble in water, resulting in a slighty alkaline solution.

i hope this part helps i will continue to research on Toothpaste's properties

6 0

3 years ago