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fgiga [73]
3 years ago
9

Among the alkaline earth metals in Group 2A/A, which is more reactive - beryllium (element 4) or strontium (element 38)?

Chemistry
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

Group 2A (or IIA) of the periodic table are the alkaline earth metals: beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). They are harder and less reactive than the alkali metals of Group 1A.

Explanation:

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Would the solubility for a substance increase by dissolving the solute with more water?
garik1379 [7]

Answer: Yes

Explanation:

With more water, the molecules of the substance have more water molecules to form bonds with, thus they are dissolved even faster at that same particular temperature.

For example: a mildly soluble substance like powdered milk get more dissolved in your teacup as water, the solvent is increased

8 0
3 years ago
For the reaction: 2 A (g) + B (s)= 2 C(s) + D (g)
jolli1 [7]

Answer:

The value of the equilibrium constant = 5.213

Explanation:

Here K_p (equilibrium constant) is referred to as the  partial pressure of product divided by the  partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation .

As such only gas appear in K_p  expression as solids takes a value of 1;

SO ; in the  given equation from the question:

2 A (g) + B (s) ----> 2 C(s) + D (g)

K_p = \dfrac{[D]}{[A]^2}

K_p = \dfrac{2.71}{0.721^2}

K_p = 5.213

The value of the equilibrium constant = 5.213

8 0
3 years ago
Question 9 of 10
DanielleElmas [232]

Answer:

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8 0
2 years ago
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Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
Cho hai điện tích q1 = 2.10-6 C, q2 = 4. 10-6C, đặt tại A và B trong không khí biết AB = 2 cm. Xác định vectơ cường độ điện trườ
Nitella [24]

Answer:

<h3>A</h3>

Explanation:

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3 years ago
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