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3 years ago

Which of these is a compound? A)air Boxygen C)carbon dioxide D)carbon

2 answers:

7 0

The answer is C because for a compound carbon and dioxide mixed together is also hard to see in the periodic table even thou yes its a part of thing

Snezhnost [94]3 years ago

6 0

The answer would be C. carbon dioxide.

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PLEASE HELP!!!!!!!

Keith_Richards [23]

Answer: The gas generated by two antacid tablets has a smaller volume.

Explanation:

Since the antiacid is the limiting reagent, we know that the more tablets there are, the more gas there will be.

This means that there will be more gas generated by the four antiacid tablets when compared to the two antiacid tablets, which gives us that the gas generated by the two antiacid tablets has a smaller volume.

6 0

2 years ago

A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi

tester [92]

Answer:

V₁ = 374.71 mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁ = 456 mL × 295 K / 359 k

V₁ = 134520 mL.K / 359 k

V₁ = 374.71 mL

3 0

3 years ago

Urea, CO(NH2)2, is manufactured on a large scale for use in producing urea-formaldehyde plastics and as a fertilizer. What is th

Pachacha [2.7K]

Answer:

5.004kg

Explanation:

Combustion of carbon

C+O2=CO2

from the relationship of molar ratio

mass of carbon/molar mass of carbon=volume of CO2 produced\molar vol(22.4 dm3)

mass of carbon =1000kg

atomic mass of carbon =12

volume of CO2 produced=1000×22.4/12

volume of CO2 produced =1866.6dm3

from the combustion reaction equation provided

CO2 (g) + 2NH3 (g) ⟶ CO (NH2 )2 (s) + H2 O(l)

applying the same relationship of molar ratio

no of mole of CO2=no of mole of urea

therefore

vol of CO2\22.4=mass of urea/molar mass of urea

molar mass of urea=60.06g/mol

from the first calculation

vol of CO2=1866.6dm3

mass of urea=1866.6×60.06/22.4

mass of urea=5004.82kg

7 0

3 years ago

Read 2 more answers

The base-dissociation constant, kb, for pyridine, c5h5n, is 1.4x10-9 the acid-dissociation constant, ka, for the pyridinium ion,

sp2606 [1]

We are given the base dissociation constant, Kb, for Pyridine (C5H5N) which is 1.4x10^-9. The acid dissociation constant, Ka for the Pyridium ion or the conjugate acid of Pyridine is to be determined. We know from our chemistry classes that:

Kw = Kb * Ka

where Kw is always equal to 1x10^-14

so, to solve for Ka of Pyridium ion, substitute Kb to the equation together with Kw and solve for Ka:

1x10^-14 = 1.4x10^-9 * Ka
solve for Ka

Ka = 7.14x10^-6

Therefore, the acid dissociation constant of Pyridinium ion is 7.14x10^-6.
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5 0

3 years ago

A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO

Akimi4 [234]

Answer: The empirical formula for the given compound is $CH_2$