Does an odometer measure distance or displacement

A rocket is launched from a height of 3 m with an initial velocity of 15 m/s What is the maximum height of the rocket? When will

Fudgin [204]

If no extra acceleration is added to the rocket, then its velocity at time t is

v = 15 m/s - g t

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Also, recall that

v² - u² = 2 a ∆x

where u is initial speed, v is final speed, a is acceleration, and ∆x is net displacement.

At the rocket's maximum height ∆x, the velocity is 0. So, the maximum height is

0² - (15 m/s)² = 2 (-g) ∆x

∆x = (15 m/s)² / (2 * (9.80 m/s²)) ≈ 11.48 m

But this assumes the rocket is launched from the ground. We're given that the rocket is launced from 3 m above the ground, so we need to add this to the height above. So the maximum height is closer to 14.48 m.

As mentioned before, this happens when vertical velocity is 0:

0 = 15 m/s - g t

t = (15 m/s) / (9.80 m/s²) ≈ 1.53 s

5 0

3 years ago

10. Convert the following: a. 37.4 mL into ML b. 689 km/hr into m/s c. 34.5 m² into mm²

Snezhnost [94]

A. When we convert 37.4 mL to ML, the result obtained is 3.74×10¯⁸ ML

B. When we convert 689 km/hr to m/s, the result obtained is 191.39 m/s

C. When we convert 34.5 m² to mm², the result obtained is 3.45×10⁷ mm²

<h3>A. How to convert millimeters (mL) to megaliter (ML)</h3>

Volume (mL) = 37.4 mL
Volume (ML) =?

1 mL = 1×10¯⁹ ML

Therefore,

37.4 mL = 37.4 × 1×10¯⁹

37.4 mL = 3.74×10¯⁸ ML

Thus, 37.4 mLis equivalent to 3.74×10¯⁸ ML

<h3>B. How to convert 689 km/hr to m/s</h3>

Conversion scale

3.6 Km/hr = 1 m/s

Therefore,

689 km/hr = 689 / 3.6

689 km/hr = 191.39 m/s

Thus, 689 km/hr is equivalent to 191.39 m/s

<h3>C. How to convert 34.5 m² to mm²</h3>

Conversion scale

1 m² = 1×10⁶ mm²

Therefore,

34.5 m² = 34.5 × 1×10⁶

34.5 m² = 3.45×10⁷ mm²

Thus, 34.5 m² is equivalent to 3.45×10⁷ mm²

Learn more about conversion:

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6 0

2 years ago

I need help please..its too complicated

Charra [1.4K]

Question: What was his initial velocity?

Answer: 3.62 m/s

3 0

2 years ago

A block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so that the

bezimeni [28]

Answer:

The answer is "a, c and b"

Explanation:

Its total block power is equal to the amount of potential energy and kinetic energy.
Because the original block expansion in all situations will be the same, its potential power in all cases is the same.
Because the block in the first case has no initial speed, the block has zero film energy.
For both the second example, it also has the $v_o$ velocity, but the kinetic energy is higher among the three because its potential and kinetic energy are higher.
While over the last case the kinetic speed is greater and lower than in the first case, the total energy is also higher than the first lower than that of the second.
The greater the amplitude was its greater the total energy, therefore lower the second, during the first case the higher the amplitude.

4 0

3 years ago

What is the equation for determining the value of a specific gas constant using the universal gas constants

maria [59]

Answer:

Physically, the gas constant is the constant of proportionality that relates the energy scale in physics to the temperature scale, when a mole of particles at the stated temperature is being considered. Thus, the value of the gas constant ultimately derives from historical decisions and accidents in the setting of the energy and temperature scales, plus similar historical setting of the value of the molar scale used for the counting of particles.

Explanation:

Pa follow

3 0

3 years ago