Does an odometer measure distance or displacement

A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac

vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

$n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence

${\theta_r}$ is the angle of refraction = 90°

${n_2}$ is the refractive index of the refraction medium

${n_1}$ is the refractive index of the incidence medium

Thus,

$n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}$

The formula for the calculation of critical angle is:

${sin\theta_{critical}}=\frac {n_2}{n_1}$

Where,

${\theta_{critical}}$ is the critical angle

(b)

No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

7 0

4 years ago

Que es la energia electrica

Mnenie [13.5K]

Answer:

:) :) :) :) :) :) :) :) :)

Explanation:

:) :) :) .......

6 0

3 years ago

A rabbit trying to escape a fox runs north for 8.0 m, darts northwest for 1.0 m, then drops 1.0 m down a hole into its burrow. W

kifflom [539]

Answer:

9.61 m

Explanation:

d1 = 8 m north

d2 = 1 m north west

d3 = 1 m vertically down

Write the displacements in vector form

$\overrightarrow{d_{1}}=8\widehat{j}m$

$\overrightarrow{d_{2}}=1 \left ( -Cos45\widehat{i}+Sin45\widehat{j} \right )m$

$\overrightarrow{d_{2}}=\left ( -0.707\widehat{i}+0.707\widehat{j} \right )m$

$\overrightarrow{d_{3}}=-1\widehat{k}m$

The resultant displacement is given by

$\overrightarrow{d}=\overrightarrow{d_{1}}+ \overrightarrow{d_{2}} +\overrightarrow{d_{3}}$

$\overrightarrow{d}=-0.707\widehat{i}+ 8.707\widehat{j} - 4\widehat{k}m$

The magnitude of displacement is given by

d =

$\sqrt{\left ( -0.707 \right )^{2}+\left ( 8.707 \right )^{2}+\left ( -4 \right )^{2}}$

d = 9.61 m

4 0

3 years ago

Suppose a car is traveling in the negative x-direction and comes to a stop. What is the sign of that car’s acceleration? How do

Oduvanchick [21]

We have equation of motion v = u + at

Where v = final velocity, u = initial velocity, a = acceleration, and t = time

In this case car is travelling in -x direction

Velocity of car = displacement / time

Since displacement value is increasing in negative x axis it's initial velocity is negative

And it's final velocity is zero since it comes to rest, and time is also positive

So, v= u+ at => 0 = -u + at

So, a = u/t

Which is positive and along positive X - direction

7 0

4 years ago

A proton, traveling with a velocity of 4.6 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.0

Kobotan [32]

Answer:

$B = 0.0815 T$

since the direction of force is along south so the magnetic field must be upwards

Explanation:

Force on moving charge in magnetic field is given as

$F = q(\vec v \times \vec B)$

here we know this is force on proton

so we have

$q = 1.6 \times 10^{-19} C$

$F = 6.0 \times 10^{-14} (-\hat j) N$

also we know that the velocity of charge is

$v = 4.6 \times 10^6 \hat i m/s$

now from above formula we have

$(6.0 \times 10^{-14}) = (1.6 \times 10^{-19})(4.6 \times 10^6)B$

$B = 0.0815 T$

since the direction of force is along south so the magnetic field must be upwards

6 0

4 years ago