Answer:


Explanation:
From the question we are told that
Initial velocity of 60 m/s
Wind speed 
Generally Resolving vector mathematically

Generally the equation Pythagoras theorem is given mathematically by



Therefore Resultant velocity (m/s)

b)Resultant direction
Generally the equation for solving Resultant direction

Therefore


I think it is 500 cm. Hope I helped!
Answer:
<em>d. 268 s</em>
Explanation:
<u>Constant Speed Motion</u>
An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.
Expressed in a simple equation, we have:

Where
v = Speed of the object
d = Distance traveled
t = Time taken to travel d.
From the equation above, we can solve for d:
d = v . t
And we can also solve it for t:

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.
The time it will take for them to meet is:

t = 0.0746 hours
Converting to seconds: 0.0746*3600 = 268.56
The closest answer is d. 268 s
The statement that best describes the production of energy in the Sun is nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.
<h3>How is energy produced in the sun?</h3>
Sun is a major source of renewable energy to the Earth. This energy serves various purposes by living organisms.
However, the energy is generated as a result of nuclear fusion, which is the combination of smaller particles to form a larger one.
Therefore, the statement that best describes the production of energy in the Sun is nuclei with less mass combine to form nuclei with more mass in the Sun’s core and release energy.
Learn more about energy at: brainly.com/question/1932868
#SPJ1
Answer:
The inlet velocity is 21.9 m/s.
The mass flow rate at reach exit is 1.7 kg/s.
Explanation:
Given that,
Mass flow rate = 2 kg/s
Diameter of inlet pipe = 5.2 cm
Fifteen percent of the flow leaves through location (2) and the remainder leaves at (3)
The mass flow rate is

We need to calculate the mass flow rate at reach exit
Using formula of mass



We need to calculate the inlet velocity
Using formula of velocity

Put the value into the formula


Hence, The inlet velocity is 21.9 m/s.
The mass flow rate at reach exit is 1.7 kg/s.