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4 years ago

I need help with this physics question

Physics

1 answer:

insens350 [35]4 years ago

4 0

It's impossible to describe WHERE a place is without mentioning ANOTHER place.

... Across the street from -- the bank.
... Next door to -- my house.
... 30 miles west of -- Chicago.
... Up above -- the tree.
... Two days ride out of -- Tulsa.
... Halfway home from -- school.
... Twice as far from Earth as -- the moon is.
... The first seat in -- the second row.
... Behind -- the dog's left ear.
... At the bottom of -- the pool.
... On the tip of -- my tongue.
... In the front seat of -- the car.
... I saw you in -- my dream.
... You're always on -- my mind.

The question is trying to get you to realize that to get from a reference point to a certain position, you have to know

How far
and
In what direction.

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Timmy drove 2/5 of a journey at an average speed of 20 mph.

mixer [17]

Answer:

4hr

Explanation:

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3 years ago

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Two gratings A and B have slit separations dA and dB, respectively. They are used with the same light and the same observation s

77julia77 [94]

Answer:

a) dB / dA = 2 ,

b) Network B Network A

2 1

4 2

6 3

Explanation:

a) The expression for grating diffraction is

d sin θ = m λ

where d the distance between two slits, λ the wavelength and m an integer that represents the diffraction range

In this exercise we are told that the two spectra are in the same position, let's write the expression for each network

Network A

m = 1

sin θ = 1 λ / dA

Network B

m = 2

sin θ = 2 λ / dB

they ask us for the relationship between the distances, we match the equations

λ / dA) = 2 λ / dB

dB / dA = 2

b) let's write the equation of the networks

sin θ = m_A λ / dA

sin θ = m_B λ / dB

we equalize

m_A λ/ dA = m_B λ / dB

we use that

dB / dA = 2

m_A 2 = m_B

therefore the overlapping orders are

Network B Network A

2 1

4 2

6 3

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3 years ago

Hunter-gatherer societies had the benefit of _____.

mario62 [17]

Your answer would be D- Knowledge of the environment.
I hope this helped... ;)

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A 70kg car drives through a curve with radius 50m. What is the minimum angle the road should be tilted to keep the car on the ro

worty [1.4K]

when car moves along a circular path then centripetal force for taking turn will be provided by the component of normal force

Let the road is tilted by some angle

so force equations are given as

$F_n cos\theta = mg$

$F_n sin\theta = \frac{mv^2}{R}$

now divide two equations

$tan\theta = \frac{v^2}{Rg}$

now as it is given to us that

$v = 80 km/h$

$v = 80* \frac{5}{18} = 22.2 m/s$

$R = 50 m$

now we have

$tan\theta = \frac{22.2^2}{50*9.8}$

$tan\theta = 1$

$\theta = tan^{-1}1$

$\theta = 45^0$

so it is inclined at an angle of 45 degree

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3 years ago

During a softball game, a shortstop catch a ground ball. The action forces is the ball pushing on the glove. What is the reactio

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<span>The reaction force would be the exact opposite of the action. In this case, choice (c) would be the most correct. If the action is the ball pushing the glove, the reaction would then be the glove pushing back on the ball.</span>

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