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2 years ago

In a biome there are many animals that eat one another creating a

Chemistry

2 answers:

yuradex [85]2 years ago

8 0

Answer: Food Chain

Explanation: In a food chain, energy is passed from one link to another. Many organisms cannot make their own food, so rely on eah other for nourishment.

oksano4ka [1.4K]2 years ago

3 0

Food chain because they just keep eating each other

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How do you convert 134kj to Calories?

Sonja [21]

1 kilo joule = 0.239006 calories
134 kilo joule = 134 x 0.239006
= 32.026804 calories

5 0

2 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

2 years ago

The concentration of an additive in a standard sample of palm oil was measured 6 times and the following results were obtained:

Lerok [7]

In the data, 0.20 ppm is an outlier and this can be rejected if there is a 95% confidence level.

<h3>What is an outlier?</h3>

When analyzing data an outlier is a value that is abnormal or too different from other data. In the case presented 0.20 can be tagged as an outlier because other values such as 0.11, 0.12, 0.13, and 0.14 are similar while 0.20 is outside this range.

<h3>Should this piece of data be rejected?</h3>

The general rule is that if there is a 95% of confidence or higher you can reject an outlier, knowing the other data occurs 95% of the time, and therefore the outlier is improbable.

Based on this, you can reject an outlier if the confidence level is 95%.

Learn more about outlier in: brainly.com/question/9933184

7 0

2 years ago

Consider this reaction 2Mg(s)+O2(g) ———> 2MgO(s) What volume (in milliners) of gas is required to react with 4.03 g Mg at STP

nydimaria [60]

The volume of a gas that is required yo react with 4.03 g mg at STP is 1856 ml

calculation/

calculate the moles of Mg used

moles=mass/molar mass

moles of Mg is therefore=4.03 g/ 24.3 g/mol=0.1658 moles

by use of mole ratio of Mg:O2 from the equation which is 2:1

the moles 02=0.1679 x1/20.0829 moles

at STP 1 mole of a gas= 22.4 l

0.0895 moles=? L

by cross multiplication

=0.0895 moles x22.4 l/ 1 mole=1.8570 L

into Ml = 1.8570 x1000=1856 ml approximately to 1860

6 0

2 years ago

How does the digestive system work with the muscular system?

soldier1979 [14.2K]

Answer:

the answer is not d because you can pee without moving. so its a because without the food nutrient no part of our body can work

5 0

2 years ago