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Tcecarenko [31]
3 years ago
12

Can some balance the equation?FeBr3 + H2SO --> Fe2(SO4)3 + HBr​

Chemistry
1 answer:
nadezda [96]3 years ago
7 0

Answer:

2 FeBr3 + 3 H2So4 = Fe2(So4)3 + 6 HBr

Explanation:

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The density of Nitrogen (N2) gas in a 4.32 L container at our
scoundrel [369]

Answer:

δ N2(g) = 1.1825 g/L

Explanation:

  • δ ≡ m/v
  • Mw N2(g) = 28.0134 g/mol

ideal gas:

  • PV = RTn

∴ P = (837 torr)×( atm/760 torr) = 1.1013 atm

∴ T = 45.0 °C + 273.15 = 318.15 K

∴ R = 0.082 atm.L/K.mol

⇒ n/V = P/R.T

⇒ n/V = (1.1013 atm) / ((0.082 atm.L/K.mol)(318.15 k))

⇒ n/V = 0.0422 mol/L

⇒ δ N2(g) = (0.042 mol/L)×(28.0134 g/mol) = 1.1825 g/L

5 0
3 years ago
PLEASE HELP!!!!! NEED HELP ASAP!!!!!
Anarel [89]

Answer:

1.BaCO3 2.MgBr2 3.aluminum and oxygen 4.Potassium chloride

Explanation:

3 0
2 years ago
Integrated rate law for second order unimolecular irreversible
kirill115 [55]

Answer:

The rate law for second order unimolecular irreversible reaction is

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

Explanation:

A second order unimolecular irreversible reaction is

2A → B

Thus the rate of the reaction is

v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}

rearranging the ecuation

-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}

Integrating between times 0 to <em>t </em>and between the concentrations of [A]_{0} to <em>[A].</em>

\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}

Solving the integral

\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }

5 0
3 years ago
Explain the advantage of using scientific names,
posledela

Answer:

Clarity and precision - these names are unique with each creature having only one scientific name. Helps avoid confusion created by common names. 3. Universal recognition - scientific names are standardised and accepted universally

Explanation:

4 0
2 years ago
Convert 32.56 km/hr into ft/hr
Gekata [30.6K]
Note that
1 m = 3.2808 ft

Therefore
1 km = 3280.8 ft
and
32.56 \,  \frac{km}{h} = (32.56 \,  \frac{km}{h})*(3280.8 \,  \frac{ft}{km}) =  1.0682 \, \times 10^{5} \, \frac{ft}{h}

Answer: 1.0682 x 10⁵ ft/hr

8 0
2 years ago
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