Answer:
is the total displacement (volume) of the submarine.
Explanation:
Mass of water carried by submarine at 1000 ft depth = m = 2100 kg
The density of seawater at 1000 ft depth = d = 
Volume of the water displaced = V= ?
Total displacement of the submarine = Volume of the water displaced = V
is the total displacement (volume) of the submarine.
Answer: 4.5 x 10e-7
Explanation: 450 x 1e+9 = correct answer
Multiply amount of nanometers by 1e+9 to get the approximate result in meters.
5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
Answer:- There are 
moles.
Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is 
and it's molar mass is 294.31 grams per mole.
mg are converted to grams and then the grams are converted to moles as:
= moles of aspartame
So, there would be moles of aspartame in 1.00 mg of it.
Answer:
(C5H7)8
Explanation:
It's empirical formula is given as; C5H7
Molar mass of carbon(C) = 12 g/mol
Molar mass of hydrogen(H) = 1 g/mol
We are told that it's molar mass is 536 g/mol.
To find the molecular formula;
Molecular formula = n × empirical formula
Thus;
n = 536/((12 × 5) + (1 × 7))
n = 8
Thus;
Molecular formula = (C5H7)8
