Anions: negatively charged atoms
Cations: positively charged atoms (CAT-ions are PAWS-itively charged)
Anode: positively charged electrode that allows electrical current flow (positive end of battery)
Cathode: negatively charged electrode that allows electrical current flow (negative end of batter)
v2 = ?
m1 = 10kg
m2 = 70kg
v1 = 4m/s
E1 = E2
E1 = 1/2 * m1 * v1^2 = 1/2 * 10kg * 4m/s^2 = 80J
E2 = 1/2 * m2 * v2^2 = 80 J
v2 = √(E2/(2 * m2)) = √(80J/(2 * 70kg)) = about 0.76m/s
Answer:
933. 3kg
Explanation:
We are given that
Mass,m=2000 kg
Initial speed,u=4.4 m/s
We have to find the maximum mass of grain if the speed of loaded freight car must not go below 3.0 m/s.
Final speed,v=3 m/s
By conservation of momentum
Initial momentum=Final momentum

Substitute the values



Mass of freight loaded car=2933.3 kg
Mass of grains=2933.3-2000=933.3 kg
Hence, the maximum mass of grains that it can accept=933.3 kg
Answer:
Jyftfufhfucyf fyfycyxycydyd
Explanation:
Ufivucjvk