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Verdich [7]
3 years ago
9

Predict: During a solar eclipse, our view of the sun is blocked by the moon. In the diagramam, draw where you think the moon is

located when the observer on Earth is experiencing a solar eclipse
☀️

Physics
1 answer:
olya-2409 [2.1K]3 years ago
8 0

As it states, the "Sun is blocked by the moon". This means, you'd draw the moon in front of the sun, filling most of sun in the diagram. In 2017, we actually got to experience this! Try and think back to any memories you may have looking through solar glasses.

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Help please physics!!!
Hitman42 [59]

Answer:

I think c is the answer.....

6 0
3 years ago
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Find the electric flux passing through the 45° surface of an upright circular cone with a base diameter of 4 m if the electric f
alexgriva [62]

Answer:

electric flux = 177.625 N-m²/C

Explanation:

given data

angle = 45°

diameter = 4 m

electric field E = 20 N/C

to find out

electric flux

solution

we know electric flux formula that is

electric flux = E × A × cosθ     ..............1

here A is area that is

Area = πd²/4 = π(4)²/4 = 12.56 m²

now put all value in equation 1

electric flux = 20 × 12.56 × cos45

electric flux = 177.625 N-m²/C

8 0
3 years ago
A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im
vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}

\dfrac{1}{v}=\dfrac{7}{690}

v=98.57\ cm

We need to calculate the height of the image

Using formula of height

\dfrac{h'}{h}=\dfrac{-v}{u}

Where, h' = height of image

h = height of object

\dfrac{h'}{4}=\dfrac{-98.57}{-30}

h'=\dfrac{98.57\times4}{30}

h'=13.14\ cm

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}

\dfrac{1}{v}=-\dfrac{10}{299}

v=-29.9\ cm

We need to calculate the height of the image

\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}

h=-\dfrac{29.9\times4}{13.0}

h=-9.2\ cm

The image is virtual and erect.

Hence, This is required solution.

6 0
4 years ago
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antiseptic1488 [7]

Answer:

I think That All the atoms of a given element are identical in that they have the same number of protons

Explanation:

3 0
3 years ago
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Explain how bats use ultrasound to catch a prey​
Gnoma [55]

Answer:

Ultrasound is used by bats to navigate (move) and catch prey. Ultrasonic squeaks are produced by bats. These squeaks ponder prey and then return to the bat's ear. This provides bats with information about the location of prey, allowing them to catch it.

Explanation:

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