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Tomtit [17]
4 years ago
5

Feeling a bit better about not getting the Nobel Prize, Meitner drove home from the rink. If her 1500kg car accelerated from res

t to a speed of 20 m/s in 10 seconds, what was the force exerted by the car engine?
Physics
1 answer:
lyudmila [28]4 years ago
5 0

Answer:

<em>The force exerted by the car engine was 3000 N</em>

Explanation:

<u>Mechanical Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F=m.a

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+a.t

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

The question describes how Meitner drove home taking her car from rest to a speed of 20 m/s in 10 seconds. This provides us the following data:

vf=20 m/s, v0=0 (rest), t = 10 seconds.

From the kinematics equation, we can solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{20\ m/s-0}{10\ s}=2\ m/s^2

The force exerted by the car engine was:

F=1500\ kg\cdot 2\ m/s^2

F=3000\ N

The force exerted by the car engine was 3000 N

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a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
Katyanochek1 [597]
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
where F is force,
m is mass, and 
a is acceleration

Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

3 0
3 years ago
Which bmi score listed below is considered over weight?
valentinak56 [21]
I don't see any answer choices, but if I remember correctly, the overweight BMI score is 20-22 and up. Probably 22 and up.
5 0
4 years ago
A roller-coaster car has a mass of 1080 kg when fully loaded with passengers. As the car passes over the top of a circular hill
Dmitriy789 [7]

Answer:

(a): The normal force on the car  from the track when the car's speed is v= 7.6 m/s  is  FN= -6696 N.

(b): The normal force on the car from the track when the car's speed is v= 17 m/s is FN= 8912.7 N.

Explanation:

m= 1080 kg

r= 16m

v1= 7.6 m/s

v2= 17 m/s

g= 9.81 m/s²

v1= w1*r

w1= v1/r

w1= 0.475 rad/s

ac1= w1² * r

ac1= 3.61 m/s²

FN= m * (ac1 - g)

FN= -6696 N    (a)

-----------------------------------------------------

v2= w2*r

w2= v2/r

w2= 1.06 rad/s

ac2= w2² * r

ac2= 18.06 m/s²

FN= m * (ac2 - g)

FN= 8912.7 N    (b)

4 0
3 years ago
A heat pump that operates on the ideal vapor-compression cycle with refrigerant-134a is used to heat a house. The mass flow rate
Savatey [412]

(a)  

Use “saturated refrigerant-134a pressure tableâ€, to find $ , h ,           and of refrigerant-134a, at 320kPa (P) .

     h_{1} h_{g} = 251.93kJ/kg

    s_{1} (s_g}) =0.93026 kJ/kg-K

    v_{1}(v_{g}) =0.063681 m/kg

we solve h_{6} ,

h_{6} = 282.62 kj/kg

h_{3} (h_{f)} = 127.25 kJ/kg

We use this formula for finding Q_{n}

Q_n}  =( h_{2} - h_{3}  )

      = 38.8 kw

(b)

Find the COP of the heat pump (COP_{R}) .

(COP_{R})  = q_{L} /w_{in}

COP_{R} = (282.62 -127.25) / (282.62-251.93)

          = 5.06

What is evaporator pressures ?

Valves for regulating evaporator pressure

Although the compressor suction pressure may be lower, evaporator pressure regulation (EPR) valves can be employed in the suction line to prevent the evaporator pressure from dropping below a set or controlled value.

An EPR valve is used for the following tasks:

1. Prevent potential damage to a liquid chilling evaporator from the liquid freezing.

2. Prevent frost from accumulating on an air-cooling evaporator when it is near freezing point or when operation cannot be interrupted by a brief failure.

3. Permit the operation of two or more evaporators with the same compressor at various load temperatures.

4. Vary the evaporator pressure in accordance with a fluctuating load that is managed by the load temperature.

Learn more about evaporator pressures visit this link:

brainly.com/app/ask?q=What+is+evaporator+pressures+

#SPJ4

7 0
1 year ago
What is the term for the circular movement of material inside Earth's mantle?
Gala2k [10]

Answer:

convection currents is the answer

5 0
3 years ago
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