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Tomtit [17]
4 years ago
5

Feeling a bit better about not getting the Nobel Prize, Meitner drove home from the rink. If her 1500kg car accelerated from res

t to a speed of 20 m/s in 10 seconds, what was the force exerted by the car engine?
Physics
1 answer:
lyudmila [28]4 years ago
5 0

Answer:

<em>The force exerted by the car engine was 3000 N</em>

Explanation:

<u>Mechanical Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F=m.a

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+a.t

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

The question describes how Meitner drove home taking her car from rest to a speed of 20 m/s in 10 seconds. This provides us the following data:

vf=20 m/s, v0=0 (rest), t = 10 seconds.

From the kinematics equation, we can solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{20\ m/s-0}{10\ s}=2\ m/s^2

The force exerted by the car engine was:

F=1500\ kg\cdot 2\ m/s^2

F=3000\ N

The force exerted by the car engine was 3000 N

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