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3 years ago

12

A container of gas is initially at 0.500 atm and 25 degrees Celsius, what will be the pressure at 125 degrees Celsius?

1 answer:

vekshin13 years ago

3 0

0.688 would be the correct answer!

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Use Boyle's Law to solve the following problem. A 400 mL sample of a gas is at 10

zubka84 [21]

Answer:

v2 = 100 Ml OR 0.1 Liters

Explanation:

(400 Ml) (10 atm) = (v2) (40 atm)

4000 = 40v2

100 Ml = v2

Liters = ml / 1000

Liters = 100 / 1000

Liters = 0.1

4 0

3 years ago

Calculate the ratio of H+ ions to OH– ions at a pH = 8. Find the concentration of H+ ions to OH– ions listed in Table B of your

goldenfox [79]

Answer:

0.00000001 mol/L

0.000001 mol/L

0.01: 1 OR 1: 100

Explanation:

Just did it

8 1

3 years ago

Read 2 more answers

How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol

Goshia [24]

Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

Given:

Current $I = 14.9$ A

Faraday constant $= 96485$ $\frac{C}{mole}$

Molar mass of Ni $= 58.69$ $\frac{g}{mole}$

Mass of Ni $= 0.94$ g

First find the no. moles in Ni solution,

Moles of Ni $= \frac{0.94}{58.69}$

$= 0.02$ mol

From the below reaction,

$Ni^{2+} + 2e$ ⇆ $Ni_{(s)}$

Above reaction shows "1 mol of $Ni^{2+}$ requires 2 mol of electron to form 1 mol of $Ni_{(s)}$ "

So for finding charge flow in this reaction we write,

$=$ $0.02 \times \frac{2 }{1 } \times 96485 \frac{C}{mol}$

Charge flow $= 3859.4$ C

For finding time of reaction,

$I = \frac{q}{t}$

Where $q =$ charge flow

$t = \frac{q}{I}$

$t = \frac{3859.4}{14.9}$

$t = 259.02$ sec

Therefore, time take to deposit Ni is 259.02 sec.

3 0

3 years ago

Mg(s) + ½O2(g) → MgO(s) + 146 kcal/mole H2(g) + ½O2(g) → H2O(g), ΔH = -57.82 kcal/mole What type of reaction is represented by t

adell [148]

Answer is: both reactions are exothermic.

<span>In exothermic reactions, heat is released and enthalpy of reaction is less than zero (as it show second chemical reaction).
According to Le Chatelier's principle when the reaction is <span>exothermic heat is included as a product (as it show first chemical reaction).</span></span>

7 0

3 years ago

Which of the following is not equal to 485 L?

ELEN [110]

Answer:

$4.85 * 10^4\ mL$

Explanation:

Given

485 L

Required

Determine the measurement not equal to 485L

$0.485\ kL$

<em>From standard unit of conversion;</em>

1 KL = 1000 L

<em>Multiply both sides by 485</em>

$485 * 1 KL = 485 * 1000 L$

$485KL = 485000L$

<em>Divide both sides by 1000</em>

$\frac{485KL}{1000} = \frac{485000L}{1000}$

$0.485KL = 485L$ ---- This is equivalent

---------------------------------------------------------------------------------------------

$4.85 * 10^4\ mL$

<em>From standard unit of conversion;</em>

1000 mL = 1 L

<em>Multiply both sides by 485</em>

$485 * 1000 mL = 1 L * 485$

$485000\ mL = 485\ L$

Convert to standard form

$4.85 * 10^5\ mL = 485\ L$

Hence; $4.85 * 10^4\ mL$ is not equivalent to 485L

---------------------------------------------------------------------------------------------

$48500 \ cL$

<em>From standard unit of conversion;</em>

100 cL = 1 L

<em>Multiply both sides by 485</em>

$485 * 100 cL = 1 L * 485$

$48500\ cL = 485\ L$

Convert to standard form

$4.85 * 10^4\ cL = 485\ L$ ---- This is equivalent

---------------------------------------------------------------------------------------------

$4.85 * 10^8 \$ μL

<em>From standard unit of conversion;</em>

1000000 μL = 1 L

<em>Multiply both sides by 485</em>

$485 * 1000000uL = 1 L * 485$

$485000000uL = 485\ L$

Convert to standard form

$4.85 * 10^8\ uL = 485\ L$ ---- This is equivalent

From the list of given options;

$4.85 * 10^4\ mL$ is not equivalent to 485L

4 0

3 years ago