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Andrew [12]
3 years ago
11

What is the number of moles in 40.0 L of He gas at STP?

Chemistry
1 answer:
Alla [95]3 years ago
8 0

Answer: There are 1.78 moles in 40.0 L of He gas at STP

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (STP)

V = Volume of gas = 40.0  L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K   (STP)

n=\frac{PV}{RT}

n=\frac{1atm\times 40.0L}{0.0821Latm/K mol\times 273K}=1.78moles

Thus there are 1.78 moles in 40.0 L of He gas at STP

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Answer:

M_2=3.34x10^{-3}M

Explanation:

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In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

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Answer:

 (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

Explanation:

Data Give:

Reaction between ammonium phosphate solution and solution of aluminum nitrate

  • Write a balanced chemical equation
  • include phase symbols

Details:

To write a balanced chemical equation we have to know formula units of compounds or molecules

Formula units

ammonium phosphate : (NH₄)₃PO₄

aluminum nitrate: Al(NO₃)₃

ammonium nitrate: NH₄NO₃

Now to write a chemical equation

  • we have to write the chemical formulas  or formula unit of each compound
  • write the reactant on left side of the arrow
  • write the product on the right side of the arrow
  • put a plus sign in 2 reactants and products on each side of the arrow
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So the Reaction will be

                      (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + NH₄NO₃

Now balance the Chemical equation

                     (NH₄)₃PO₄ + Al(NO₃)₃ -----------→  AlPO₄ + 3NH₄NO₃

Now write the phase Symbols

                     (NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→  AlPO₄(l) + 3NH₄NO₃(l)

all compounds in the reaction are in liquid form and soluble in water

*** Note:

There is no aluminum nitrite in chemicals formulas

Also ammonium nitrite can not be used in pure isolated form due to its highly instability

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The significant figures of a measured quantity are defined as all the digits known with certainty and the first uncertain or estimated digit.

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1. Digits from 1 to 9 are always significant and have infinite number of significant figures.

2. All non-zero numbers are always significant.

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