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KiRa [710]
4 years ago
5

A 38.6 kg marble slab is shown above. What is its density? Give your answer to the nearest tenth.

Chemistry
2 answers:
masya89 [10]4 years ago
7 0

Answer: 24.7

Explanation:

LuckyWell [14K]4 years ago
6 0

Answer:

Density, d=26.7\ g/cm^3

Explanation:

The attached figure shows a 38.6 kg marble slab. The dimensions of the marble slab is 23 cm × 17 cm × 4 cm

Density = mass/volume

Volume of a cuboid shape is equal to, V = 23 cm × 17 cm × 4 cm

V = 1564 cm³

Density,

d=\dfrac{38.6\times 10^3\ g}{1564\ cm^3}\\\\d=24.68\ g/cm^3

or

d=26.7\ g/cm^3

So, the density of the marble slab is 26.7\ g/cm^3.

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laiz [17]

A uniform cube is subjected to volume expansion. Each side gets decreased by 1%, then the bulk strain is 0.03.

<h3>What is Volume?</h3>

Volume is the space occupied by a three-dimensional object.

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Given that, the side cube is l, then

volume V = l³

\dfrac{\Delta V}{V} = \dfrac{3D1}{1}

For change in volume

% Change in volume = 3× % change in length

= 3 × 1%

Hence, bulk strain = 0.03.



Thus, the bulk strain is 0.03.

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5 0
3 years ago
#1.Which of the following best identifies base 1? A) purine. B) pyrimidine. C) cytosine. D) nucleotide. #2. Which of the followi
alex41 [277]
Here are the list of nucleo bases : adenine , Thymine, Guanine , Cytosine

Adenine pairs with Thymine, and Guanine pairs with Cytosine

Adenine + Guanine = Purine
Thymine + Cytosine = Pyrimidine

So the answer for number 1 will be : Purine, since Adenine is not the choice

And the answer for number 2 is Guanine

hope this helps

 


6 0
3 years ago
A 125 mL bubble of hot gases at 213 ∘C and 1.77 atm is emitted from an active volcano. Part A What is the final temperature, in
Svetach [21]

Answer:

T₂  = 242 K

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 125 mL

Initial pressure = 1.77 atm

Initial temperature = 213 °C (213 +273 = 486 K)

Final volume = 136 mL

Final pressure = 0.810 atm

Final temperature = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂T₁ / P₁V₁

T₂ = 0.810 atm × 136 mL × 486 K / 1.77 atm× 125 mL

T₂  =  53537.76 atm .mL.  K  / 221.25 atm . mL

T₂  = 242 K

6 0
3 years ago
Select The on that most applys<br><br><br> Will mark brainliest
sdas [7]

Answer:

A and C

Explanation:

7 0
3 years ago
Formula: C8H9O2N
hammer [34]
There are 9 H atoms in one molecule, so hydrogen is present in the greatest proportion by number of particles; The ratio by particles is C:H:O:N = 8:9:2:1.
8 0
3 years ago
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