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3 years ago

Lewis structure for 2O2

Chemistry

2 answers:

Mrrafil [7]3 years ago

6 0

the big number describes the number ratio in a chemical equation

so for example,

2H2 + O2 --> 2H2O means

2 moles of hydrogen reacts with one mole of oxygen to form 2 moles of water

and as you know, the small (subscript) number determines the number of atoms of that element in one molecule of a compound

so I believe that drawing a normal lewis structure ( O=O ) should be correct

scoray [572]3 years ago

4 0

Explanation:

For what I understand in the question, the "big number" is called a stoichiometric coefficient and represents the ammount of molecules of the substance that follows it ( in this case O2) involved in a reaction.

In this case there is no reaction but it asks you for the lewis structure of two molecules of oxygen (O2).

The lewis structure of oxygen is: O=O

Two molecules of it can bond by london forces or dative unions forming what is known as a dimer (two molecules of the same substance bonded).

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A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L

NeTakaya

Answer:

$\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}$

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

$P_1V_1=P_2V_2$

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

$25.0 \ L * 2.05 \ atm = P_2V_2$

The volume is decreased to 14.5 liters, but the pressure is unknown.

$25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L$

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

$\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}$

$\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2$

The units of liters cancel.

$\frac {25.0 * 2.05 \ atm }{14.5 }=P_2$

$\frac {50.25\ atm }{14.5 }=P_2$

$3.53448276 \ atm = P_2$

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

$3.53 \ atm \approx P_2$

The new pressure is approximately 3.53 atmospheres.

8 0

3 years ago

How many atoms are in 1.14 mol of sulfur trioxide

yawa3891 [41]

2.75 x 10^24

Hope this helped :)

8 0

4 years ago

SI unit for measuring distance is

MrMuchimi

The SI unit for measuring distance is the meter.
I attached a table of SI measurements for you :)
Hope this helped!

6 0

3 years ago

What quantity of copper is deposited by the same quantity of electricity that deposited 9g of aluminum

klio [65]

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

3 0

3 years ago

Is the haber process for the industrial synthesis of ammonia spontaneous or nonspontaneous under standard conditions at 25 ∘c? n

Ostrovityanka [42]

The industrial synthesis of ammonia is spontaneous.

to to prove this one calculate the gibbs free energy(delta G)

= delta G = Delta H -T delta s

delta H = -92.2 kj in joules -92.2 x1000 =-92200j
delta s = -199j/k
T= 25+273= 298k

delta G is therefore= -92200-298(-199)=-32898j
since delta G is negative the reaction is therefore spontaneous

6 0

4 years ago