Answer:
the Molecular formula will be; C10H14O
Explanation:
Given the data in the question;
Chrysanthenone is an unsaturated ketone,
it has M+ = 150 and contains 2 double bond(s) and 2 ring(s).
molecular formula = ?
we know that ketone contain 1 oxygen and mass of oxygen is 16
so mass of the C and H remaining will be;
⇒ 150 - 16 = 134
Now we determine the number of C atoms;
⇒ 134 / 13 = 10
hydrocarbon with 10 hydrogen atom have CnH2n+2 means
⇒ ( 10 × 2 ) +2 = 22 hydrogens
But then we have 3 unsaturation meaning 6 hydrogens less and also we have ring meaning 2 more hydrogens
⇒ 22 - 6 - 2 = 14
Hence the Molecular formula will be; C10H14O
Answer:
The answer to your question is below
Explanation:
There are 4 types of chemical reactions:
- Synthesis is when two elements or compounds form only one compound.
- Decomposition is when 1 compound is broken into 2 or more products.
- Single replacement is when one element is replaced by another element.
- Double replacement is when the cations of two compounds are interchanged.
6.- Synthesis Al + 3Cl ⇒ AlCl₃
7.- Double replacement 2NaOH + H₂SO₄ ⇒ Na₂SO₄ + 2H₂O
8.- Decomposition Ni(ClO₃)₂ ⇒ NiCl₂ + 3O₂
9.- Combustion 2C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
10.- Single replacement Zn + 2HCl ⇒ ZnCl₂ + H₂
Answer:
29% is the final concentration
Explanation:
To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:
Volume ethanol / Total volume * 100
<em>Volume ethanol:</em>
10mL * 70% = 7mL ethanol
+
20mL * 80% = 16mL ethanol
= 23mL ethanol
<em>Total volume:</em>
10mL + 20mL + 50mL = 80mL
<em>Concentration:</em>
23mL / 80mL * 100
= 29% is the final concentration
1B.a metal that lost one electron
4C a non metal that gained two electrons
Answer:
Explanation:
We use the method of titration
A titration involves finding the unknown concentration of one solution by reacting it with a solution of known concentration. The solution of unknown concentration (the analyte) is usually placed in an Erlenmeyer flask, while the solution of known concentration (titrant) is placed in a burette. The titrant is added to the analyte until the endpoint is reached usually determined by a color change. Calculations are then performed to find the unknown concentration of the analyte. Titrations are typically performed on acid/base reactions but are not limited to them.
Macid x Vacid = Mbase x Vbase
Macid = Molarity of the acid
Vacid = Volume of the acid
Mbase = Molarity of the base
Vbase = Volume of the base
If the titrant and analyte have a 1:1 mole ratio, the equation above can be used to determine the unknown concentration, if the ratio is not 1:1 then a modified version should be used
I hope you find this helpful.
