This is equivalent to having a standard enthalpy change of reaction equal to 10.611 kJ
<u>Explanation</u>:
The standard enthalpy change of reaction, Δ
H
∘
, is given to you in kilojoules per mole, which means that it corresponds to the formation of one mole of carbon dioxide.
C
(s] + O
2(g]
→
CO
2(g]
Remember, a negative enthalpy change of reaction tells you that heat is being given off, i.e. the reaction is exothermic.
First to convert grams of carbon into moles,
use carbon's molar mass(12.011 g).
Moles of C = mass in gram / molar mass
= 0.327 g / 12.011 g
Moles of C = 0.027 moles
Now, in order to determine how much heat is released by burning of 0.027 moles of carbon to form carbon-dioxide.
= 0.027 moles C 393 kJ
Heat released = 10.611 kJ.
So, when 0.027 moles of carbon react with enough oxygen gas, the reaction will give off 10.611 kJ of heat.
This is equivalent to having a standard enthalpy change of reaction equal to 10.611 kJ
N(CaCO3)=m÷M
m being the mass of the sample and M being the molar mass of the compound; Molar mass is to be obtained by adding the atomic masses of all the elements in the compound.
therefore,
n(CaCO3)=m÷M
=28g÷100 g.mol
=0.28 mol
therefore, there are 0.28 moles in 28g of Calcium Carbonate.
I don't know what you mean by just good, but electricity wise, no. In electricity they can't conduct very well and are just so called "heat carriers." They also have higher melting and/or boiling points. I found most of this on google so if you still are lost try looking up your question. Good luck! :)
It will have 98 number of electrons because the number of protons are equals to the number of electrons unless element x has isomers. if it has isomers then only it will have a different electron number but mind it the proton number will remain the same. note: if the proton number changes the whole element changes.