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Harlamova29_29 [7]
3 years ago
14

Sound is an example of ?

Physics
2 answers:
wlad13 [49]3 years ago
8 0
Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
valentina_108 [34]3 years ago
3 0
A. Longitudinal wave
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What is the momentum of a 5 kg object that has a velocity of 1.2 m/s ?
Grace [21]

Answer:

The momentum, p = 6 kg • m/s

Explanation:

Given that,

Mass of the object, m = 5 Kg

Velocity of the object, v  = 1.2 m/s

The momentum of the body is defined as the product of the mass and velocity of the body. It is denoted by the letter 'p'

                                      p = mv

Substituting the values in the above equation

                                      p = 5 Kg x 1.2 m/s

                                         = 6 kg • m/s

Hence, the momentum of the object is p = 6 kg • m/s

4 0
3 years ago
Large amplitude of sound vibrations will produce.....
user100 [1]

Answer:

louder sound.

Explanation:

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound

8 0
4 years ago
In an experiment performed in a space station, a force of 60 N causes an object to have an acceleration equal to 4m/s. What is t
Naddik [55]

I'm afraid you're not paying attention.  This question is loaded with
all the important words, and you don't recognize Newton's second
law of motion.  Didn't you notice the  "force", "acceleration", and
"mass" all over the place in there ?

Newton's 2nd law:      Force = (mass) x (acceleration)

The answer is going to be 'mass', so let's divide
each side of Newton's law by 'acceleration':

                                   Mass = (force) / (acceleration)

Now, just write in the numbers that the question gave you:

                  force =  60 newtons
       acceleration =  4 m/s²

Here's the equation again:     Mass = (force) / (acceleration)      

                                                       = (60 N) / (4 m/s²)

                                                       =  15 kg .  

3 0
4 years ago
A tennis player receives a shot with the ball (0.060 0 kg) traveling horizontally at 56.0 m/s and returns the shot with the ball
Fofino [41]

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = 56 m/s

Final speed of the ball, v = -34.5 m/s (opposite direction)

(a) Let J is the impulse delivered to the ball by the racquet. It is equal to the change in momentum of the object as :

J=m(v-u)

J=0.06\ kg(-34.5\ m/s-56\ m/s)

J = -5.43 kg-m/s

(b) The work done by the racquet on thee ball is equal to the change in kinetic energy as :

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 0.06((-34.5)^2-(56)^2)

W = -58.372 Joules

7 0
3 years ago
The pulley system below uses a gasoline engine to raise a drill head up through a smooth drill pipe. The engine provides a const
polet [3.4K]

NB: The diagram of the pulley system is not shown but the information provided is sufficient to answer the question

Answer:

Power = 2702.56 W

Explanation:

Let the power consumed be P

Energy expended = E = mgh

height, h = 5 m

E = 80 * 9.8 * 5

E = 3920 J

Power = \frac{Energy}{time}

To calculate the time, t

From F = ma

F = 900 N

900 = 80 a

a = 900/80

a = 11.25 m/s²

From the equation of motion, s = ut + 0.5at^{2}

The drill head starts from rest, u = 0 m/s

5 = 0 * t + (0.5*11.25*t^{2} )\\5 = 5.625t^{2}\\t^{2} = 5/5.625\\t^{2} = 0.889\\t = 0.943 s

Power, P = E/t

P = 3920/0.0.943

P = 4157.79 W

But Efficiency, E = 0.65

P = 0.65 * 4157.79

Power = 2702.56 W

6 0
3 years ago
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