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Verdich [7]
3 years ago
11

It takes a slug 20 minutes to travel from the grass to the trash can , a trip of 15 meters. How far could the slug travel in 60

minutes (help me please)
Physics
1 answer:
inn [45]3 years ago
5 0

Answer:

45 meters

Explanation:

20 min = 15 meters

So if 20 x 3 = 60

you have to do 3 x 15 !

- which equals to 45 <3

<u>- mark me brainlest pls . </u>

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Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now _____ .
Arte-miy333 [17]
<span>Neo and Morpheus's masses have gained a velocity (not equal to zero) which means their momentum is now based on gravity and friction alone.</span>
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2 years ago
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During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the c
oksian1 [2.3K]

Answer:

85.5 km/h

Explanation:

t_{1} = time interval for first phase = 14 min = \frac{14}{60} h = 0.233 h

t_{2} = time interval for second phase = 46 min = \frac{46}{60} h = 0.767 h

v = average speed for the entire trip = 74 km/h

v_{1} = average speed in first phase = 36 km/h

v_{2} = average speed in second phase

d_{1} = distance traveled in first phase

d_{2} = distance traveled in first phase

average speed is given as

v = \frac{d_{1} + d_{2}}{t_{1} + t_{2}}

v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}

74 = \frac{(36) (0.233) + v_{2} (0.767)}{0.233 + 0.767}

74 = (36) (0.233) + v_{2} (0.767)

v_{2} = 85.5 km/h

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3 years ago
You hang a tv on your wall. What kind of energy does it have?
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Answer:

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Explanation:

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3 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

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in this case the given volage is a square wave that can be described by the function

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to substitute in the equation let us separate the into two pairs

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             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

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