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Neko [114]
2 years ago
7

Interior crocodile alligator i drive a chevrolet movie theater​

Physics
2 answers:
Sholpan [36]2 years ago
8 0

Answer:

nah bro tesla

Explanation:

Artist 52 [7]2 years ago
6 0

Answer:

Explanation: free points i guess lol

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4.5s

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A sports car accelerates from zero to 30 mph in 1.5 s.

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3 years ago
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Answer: conduction :it transfers heat between objects that are in direct contact with eachother
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A ______________ is very general in nature, while a ________________ specifies what we want to study more specifically, suggesti
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research topic and research question (hypothesis)

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6 0
3 years ago
A spring on Earth has a 0.500 kg mass suspended from one end and the mass is displaced by 0.3 m. What will the displacement of t
julia-pushkina [17]

To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.

The extension of the spring due to the weight of the object on Earth is 0.3m, then

F_k = F_{W,E}

kx_1 = mg

The extension of the spring due to the weight of the object on Moon is a value of x_2, then

kx_2 = mg_m

Recall that gravity on the moon is a sixth of Earth's gravity.

kx_2 = m\frac{g}{6}

kx_2 = \frac{1}{6} mg

kx_2 = \frac{1}{6} kx_1

x_2 = \frac{1}{6} x_1

We have that the displacement at the earth was x_1 = 0.3m, then

x_2 = \frac{1}{6} 0.3

x_2 = 0.05m

Therefore the displacement of the mass on the spring on Moon is 0.05m

6 0
3 years ago
how would the velocity of the book change if the applied force were equal to the sliding friction force
Inessa [10]
Yes, Sliding friction opposes the movement of the book, slowing it down.sliding That's the 'kinetic' kind.. According to Newton's second law, F=ma. That is, the bear's acceleration should be proportional to the total force acting on the bear. As the bear's velocity is constant, its acceleration is zero. Therefore, the total Force acting on the bear is zero. Thus, the friction has to be equal in magnitude and opposite in direction to the bear's weight. As W=mg, we get that its weight is  <span>9.8*400=3,920 Newton. Thus, the friction acting on the bear is 3,920 Newton</span>
3 0
3 years ago
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