Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).
<h3 /><h3>Line of code for force and acceleration</h3>
- In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.
- Acceleration is a vector quantity (in that they have magnitude and direction).
- The direction of an object's acceleration is determined by the direction of the net force acting on it.
- Newton's Second Law states that the combined effect of two factors determines how much an item accelerates.
- The size of the net balance of all external forces acting on the object is, in accordance with the materials used to create it.
- It inversely proportional to its mass, whereas the magnitude of the net resultant force is directly proportional to the net force.
def force(mass, acceleration):
force_val = mass*acceleration
return force_val
10 is assigned to mass and 9.81 is assigned to acceleration
def force(10, 9.81)
So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).
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The force is -12,000 N
Explanation:
First of all, we calculate the acceleration of the ball, by using the following suvat equation:

where:
v = 0 is the final velocity of the baseball (it comes to rest)
u = 40 m/s is the initial velocity
a is the acceleration
s = 2.0 cm = 0.02 m is the displacement of the ball
Solving for a,

Now we can calculate the average force exerted on the ball, by using Newton's second law:

where
m = 300 g = 0.3 kg is the mass of the ball
is the acceleration
Substituting,

where the negative sign indicates that the direction of the force is opposite to the direction of motion of the ball.
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Acceleration = (change in speed)/(time for the change)
Change in speed = (end speed) - (start speed)
Change in speed = (10 m/s) - (20 m/s) = -10 m/s
Time for the change = 5.00 seconds
Acceleration = (-10 m/s) / (5 sec)
<em>Acceleration = -2 m/s²</em>
That's choice-A .
Answer:

Explanation:
Given,
Red light wavelength = 633 nm
width of slit = 0.320 mm
distance,d = 2.60 m
Condition of first maximum


m = 1


Width of the first minima



Now, width of the central region



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