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2 years ago

7

Mackenzie took out a payday loan for $1100 that charged a $95 fee. If the loan matures in 2 weeks, what is the approximate effec

tive interest rate of the loan?

2 answers:

Leona [35]2 years ago

5 0

Answer:

For apex , the answer is 764%

Step-by-step explanation:

Alexeev081 [22]2 years ago

4 0

We are asked to solve for the approximate effective interest rate of the loan and the given values are:
Payday load = $1100
Charge fee = $95

Solving for interest we have:
% interest = $95/$1100
% interest = 8.64 %

The answer to the problem is 8.64%.

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Does anyone know this?

weeeeeb [17]

Answer:

BC = 10.24

Step-by-step explanation:

You can use the Pythagoras theorem for this question

$a^{2}$ + $b^{2}$ = $c^{2}$

a = 8cm

b = ???

c = 13cm

We will solve for B (length BC)

$a^{2}$ + $b^{2}$ = $c^{2}$

$8^{2}$ + $b^{2}$ = $13^{2}$

Rearrange for b

$b^{2}$ = $13^{2}$ - $8^{2}$

$b^{2}$ = 105

b = $\sqrt{105}$

b = 10.24

7 0

2 years ago

A marketing research company desires to know the mean consumption of meat per week among males over age 50. A sample of 217 male

guajiro [1.7K]

Answer: (3.3, 3.5)

Step-by-step explanation:

The formula to calculate the confidence interval is given by :-

$\overline{x}\pm z^* \dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z* = critical value.

$\sigma$ = Population standard deviation.

n= Sample size.

As per given , we have

$\overline{x}=3.4$

$\sigma=0.5$

n= 217

By using z-table , the critical value for 95% confidence level : z* = 1.96

Now, the 95% confidence interval for the mean consumption of meat among males over age 50 will be :

$3.4\pm (1.96) \dfrac{0.5}{\sqrt{217}}$

$3.4\pm (1.96) \dfrac{0.5}{14.73091986}$

$3.4\pm (1.96) 0.0339422$

$3.4\pm 0.066526712\approx3.4\pm 0.1=(3.4-0.1,\ 3.4+0.1)=(3.3,\ 3.5)$

Hence, the 95% confidence interval for the mean consumption of meat among males over age 50 =(3.3, 3.5)

4 0

2 years ago

What is the mean for Doctor A’s data set on corrective lenses? What is the mean for Doctor B’s data set on corrective lenses? Wr

Nat2105 [25]

Answer: Doctor A: 751.6 Doctor B: 755.2 Doctor B has an average of 3.6 more patients wearing corrective lenses than Doctor A.

Step-by-step explanation:

To find the mean for corrective lenses, add up all of the numbers and divide by the number of data points.

Doctor A's mean:

Add up the data points: 745+726+769+765+756+742+747+748+770+738 = 7516. Count the number of data points to get 10. Divide 7516 by 10. 7516/10 = <em>751.6</em>.

Doctor B's mean:

Add up the data points: 763+736+735+759+748+756+765+761+768+761 = 7552. Divide by 10. 7552/10 = <em>755.2</em>

Difference:

755.2-751.6 = <em>3.6</em>

4 0

1 year ago

Read 2 more answers

Which fraction does not represent a rational number?

True [87]

Answer:

C

Step-by-step explanation:

You can't divide by 0 so c

8 0

2 years ago

Can someone please help me with this question

Agata [3.3K]

The volume of the styrofoam collar is approximately 1,960.35 $in^{3} .$

Step-by-step explanation:

Step 1:

The given styrofoam collar is a hollow cylinder. A hollow cylinder consists of an outer radius and an inner radius.

This given hollow cylinder has an outer radius of 8 inches and an inner radius of 5 inches. The height of the cylinder is 16 inches.

To calculate the volume of a hollow cylinder we subtract the volume of a cylinder constructed with the inner radius from the volume of a cylinder with the outer radius.

Step 2:

The volume of a cylinder, $V = \pi r^{2} h.$

For the outer cylinder, $r = 8$ inches and $h=16$ inches.

The volume of the outer cylinder, $V_{1} = \pi (8^{2})(16) = 3,216.99.$

For the inner cylinder, $r = 5$ inches and $h=16$ inches.

The volume of the inner cylinder, $V_{2} = \pi (5^{2})(16) = 1,256.637.$

Step 3:

The volume of the styrofoam collar $= V_{1} -V_{2},$

The volume of the styrofoam collar $= 3,216.99-1,256.637 = 1,960.353.$

Rounding this off, we get the volume of the styrofoam collar as 1,960.35 $in^{3} .$

4 0

3 years ago