2 Al + 6 HCl → 2 AlCl₃ + 3 H₂ (single displacement)
Ca + Br₂ → CaBr₂ (synthesis)
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O (combustion)
2 NaCl → 2 Na + Cl₂ (decomposition)
FeS + 2 HCl → FeCl₂ + H₂S (double displacement)
single displacement - is a chemical reaction of the following type: A + BC → AC + B
double displacement - is a chemical reaction of the following type: AB + CD → AC + BD
synthesis - the chemical product is obtained by combining in a synthesis the constituent elements
combustion - usually a exothermic reaction of a particular compound with oxygen
decomposition - degradation of a compound in simpler elements
What are the answer choices?
It would 47.7 because you would have to both minus the number together.
Answer:
![W=5743.1077\ J](https://tex.z-dn.net/?f=W%3D5743.1077%5C%20J)
Explanation:
The expression for the work done is:
![W=RT \ln \left( \dfrac{P_1}{P_2} \right)](https://tex.z-dn.net/?f=W%3DRT%20%5Cln%20%5Cleft%28%20%5Cdfrac%7BP_1%7D%7BP_2%7D%20%5Cright%29)
Where,
W is the amount of work done by the gas
R is Gas constant having value = 8.314 J / K mol
T is the temperature
P₁ is the initial pressure
P₂ is the final pressure
Given that:
T = 300 K
P₁ = 10 bar
P₂ = 1 bar
Applying in the equation as:
![W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)](https://tex.z-dn.net/?f=W%3D8.314%5Ctimes%20300%20%5Cln%20%5Cleft%28%20%5Cdfrac%7B10%7D%7B1%7D%20%5Cright%29)
![W=300\times \:8.314\ln \left(10\right)](https://tex.z-dn.net/?f=W%3D300%5Ctimes%20%5C%3A8.314%5Cln%20%5Cleft%2810%5Cright%29)
![W=2.30258\times \:2494.2](https://tex.z-dn.net/?f=W%3D2.30258%5Ctimes%20%5C%3A2494.2)
![W=5743.1077\ J](https://tex.z-dn.net/?f=W%3D5743.1077%5C%20J)
Answer:
If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.